What is the value of this expression when c=4 c^3/2

Answers

Answer 1
Answer:

Answer:

8

Step-by-step explanation:

c ^ 3/2

Let c = 4

4 ^ 3/2

Rewriting 4 as 2^2

2 ^2 ^3/2

We know that a^b^c = a^(b*c)

2 ^(2*3/2)

2 ^3

8

Answer 2
Answer:

therightansweris8.

pleaseseetheattachedpictureforfullsolution

Hopeithelps

Goodluckonyourassignment....


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Sheila has 10 1/2 pounds of potato salad. She wants to divide the potato salad into containers, each of which holds 2 1/4 pounds. How many containers does she need? Complete the explanation.

Answers

Answer: 5  containers

Step-by-step explanation:

Step 1

Given that

Total amount of potato salad = 10 1/2

amount of salad in each container = 2 1/4

Total number of containers = ?

Step 2

Divide the total amount of potato salad by the amount of salad each container  can hold  

 Total number of containers=10 1/2 / 2 1/4 = 21/2 x 4/9= 84/18 = 4 3/5

which can also be written as 10.5 / 2.25= 4.6  

Sheila  will need 5 containers because  4 will be filled and  additional 1 will be partially filled.

Four different beverages are sold at a​ fast-food restaurant: soft​ drinks, tea,​ coffee, and bottled water. Explain why the type of beverage sold is an example of a categorical variable

Answers

Answer:  The values of the variable can only be placed into categories.

Step-by-step explanation:

Type list of beverage sold is a categorical variable because the values of the variable can only be placed into categories.

A categorical variable, also referred to as nominal variable. is a variable which consist of two or more categories, this usually does not involve special ordering of the categories.

Solve for r , what is r equal to ?

Answers

Answer:

r= \sqrt[3]{(3V)/(4\pi)}

Step-by-step explanation:

V = (4)/(3) \pi r^3 \n\n</p><p>3V = 4\pi r^3 \n\n</p><p>r^3 = (3V)/(4\pi)\n\n</p><p>\huge \purple {r= \sqrt[3]{(3V)/(4\pi)}}

Write down the 1st term in the sequence given by t(n) = n2+4

Answers

T(N6) = n4+8 a guess been a long time check youtube recurences suck

H(x)=(x^2)+1 and K(x)=-(x^2)+4. If K(H)=0, what are the roots/solutions?a. ±i√3
b. ±i
c. ±2
d. ±1
e. ±1, ±i√3

Answers

H(x)=(x^2)+1\ \ \ \ and\ \ \ \ K(x)=-(x^2)+4. \n\nK(H)=-(H^2)+4=-(x^2+1)^2+4=4-(x^2+1)^2=\n\n.\ \ \ =2^2-(x^2+1)^2=(2-x^2-1)(2+x^2+1)=(1-x^2)(3+x^2)=\n\n.\ \ \ =(1-x)(1+x)(x^2-3\cdot i^2)=(1-x)(1+x)(x- √(3) \cdot i)(x+ √(3) \cdot i)\n\n K(H)=0\ \ \ \ \Leftrightarrow\ \ \ (1-x)(1+x)(x- √(3) \cdot i)(x+ √(3) \cdot i)=0\n\nx=1\ \ \ \ or\ \ \ \ x=-1\ \ \ \ or\ \ \ \ x=√(3) \cdot i\ \ \ \ or\ \ \ \ x=-√(3) \cdot i\n\nAns.\ e.

Write 130% as a fraction in lowest terms.

Answers

By lowest terms i'm guessing you mean the most simplified:

Firstly right the fraction in tenths (or one you know),
13/10 

The answer is 13/10 and it can't be simplified anymore