Which equation has the same soultions as x^2+6×-7=0

Answers

Answer 1
Answer: x^2+6x-7=0 \n   a=1 \n b= 6 \n c=-7 \n \n  \boxed{\boxed{\Delta=b^2-4ac}} \n \n \Delta=6^2-4*1*(-7) \n \Delta=36-(-28) \n \Delta=64 \n \Delta\ \textgreater \ 0 \Rightarrow \text{we have 2 solutions :} X_1 \ and X_2 \n \n \boxed{X_1= (-b- √(\Delta) )/(2a) } \Rightarrow X_1= (-6-8)/(2)=-7 \n \n \boxed{X_2= (-b+ √(\Delta) )/(2a) } \Rightarrow X_2= (-6+8)/(2) =1

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Which is the equation of the circle that has a diameter with endpoints located at (0, –3) and (6, 5)?

Answers

(-x-3)^2 + (y-1)^2 = 25

The terminal speed for a person parachuting (with the chute open) is abouta. 0 km/h.
b. 15 km/h.
c. 150 km/h.
d. 1500 km/h.

Answers

The terminal speed for a person parachuting with the chute open is about
15 km/h.

Hope this helped! :)

The point at which a company's profits equal zero is called the company's break-even point. let R represent a company's revenue, let C represent the company's costs, and let x represent the number of units produced and sold each day.R(x)=12x
C(x)=6.5x+22000
a) Find the firm's break-even point; that is, find x so that R=C
b) Find the values of x such that R(x)>C(x). this represents the number of units that the company must sell to earn a profit.

Answers

R ( x ) = 12 x ( revenue )
C ( x ) = 6.5 x + 22,000 ( cost )
a ) Break-even point : R ( x ) = C ( x )
12 x = 6.5 x + 22,000
12 x - 6.5 x = 22,000
5.5 x = 22,000
x = 22,000 : 5.5
x = 4,000
b ) R ( x ) > C ( x ) 
x > 4,000
The number of units that the company must sell to earn a profit is 4,001 or more.

a)     R=C implies 12x=6.5x + 22000, and then 12x - 6.5x= 22000, 5.5x= 22000, from where we find x = 22000 : 5.5,     x=4000.

b)     For R(x)>C(x), we get 12x>6.5x + 22000, which implies after the same calculation,  x>4000

Find the area under the standard normal curve to the right of \( z=2.33 \). Round your answer to four decimal places, if necessary: Answer

Answers

Answer:

0.0099

Step-by-step explanation:

To find the area under the standard normal curve to the right of \( z = 2.33 \), you're essentially looking for the probability that a randomly chosen value from the standard normal distribution is greater than 2.33.

Using a standard normal distribution table or a calculator, you can find this probability directly. The value you're looking for is the complement of the cumulative distribution function (CDF) at \( z = 2.33 \), which gives you the area to the left of \( z = 2.33 \). To find the area to the right, you subtract this value from 1.

In other words, you want to find \( 1 - P(Z \leq 2.33) \), where \( Z \) is a standard normal random variable.

Using a calculator or a standard normal distribution table, you will find that \( P(Z \leq 2.33) \approx 0.9901 \).

So, the area under the standard normal curve to the right of \( z = 2.33 \) is approximately:

\[ 1 - 0.9901 = 0.0099 \]

Rounded to four decimal places, the answer is approximately 0.0099.

Please choose my answer as brainliest.

1. Determine the magnitude of the resultant force acting on the plate and its direction, measured counter-clockwise from the positive x axis.F1 = 900 N
F2 = 750 N
F3 = 650 N





A diagram is attached to this question.

Answers

F1 . . . 100% of it = 900N is in the +x direction.

F2 . . . 70.7% of it (cos45°, 530.3N) is in the +x direction,
and 70.7% of it (sin45°, 530.3N) is in the +y direction.

F3 . . . 80% of it (520N) is in the -x direction,
and 60% of it (390N) is in the +y direction.

Total x-component:  900 + 530.3 - 520  =  1,950.3 N

Total y-component:  530.3 + 390  =  920.3 N

Magnitude of the resultant = √ (x²  +  y²)

                                       = √(1950.3²  +  920.3²)

                                       =  √4,650,070.09

                                       =   2,156.4 N  .

Angle of the resultant, measured counterclockwise
from the +x axis, is 
 
                               tan⁻¹  (y / x)

                         =    tan⁻¹  (920.3 / 1950.3)

                         =    tan⁻¹  (0.4719)

                         =    about    25.3°  .

Caution:
The same fatigue that degrades my ability to READ the question accurately
may also compromise the accuracy of my solutions.  Before you use this
answer for anything, check it, check it, check it !

 

A foreman for an injection-molding firm admits that on 55% of his shifts, he forgets to shut off the injection machine on his line. This causes the machine to overheat, increasing the probability that a defective molding will be produced during the early morning run from 3% to 15%. The plant manager randomly selects a molding from the early morning run and discovers it is defective. What is the probability that the foreman forgot to shut off the machine the previous night?

Answers

Answer:

0.8594

Step-by-step explanation:

Let a denote the event of forgetting to shut off machine and b be the event of being defective.

-A foreman forgets to shut off machine 55% of the time.

-If he forgets, 15% of molds are defective.

-If he does not, 3% of molds are defective.

#The probability that he forgot to shut off the machine is calculated as:

P(a \ and \ b)=0.55* 0.15\n\n=0.0825\n\n

P(a and ~b)=0.55(1-0.15)=0.4675

P(~a and b) = (1-0.55)*0.03=0.0135

P(~a and ~b) = (1-0.55)*(1-0.03)=0.4365

#Conditional probability is defined as:

P(a|b)=(P(a \ and\  b))/(P(a))\n\n=(P(a \ and \ b))/([(P(a \ and \ b)+P(\~a \ and \ b))\n\n\n=(0.0825)/(0.0825+0.0135)\n\n\n=0.8594

Hence,  the probability that the foreman forgot to shut off the machine the previous night is 0.8594