The coordinates of parallelogram PVWZ are P(0, 0), V(a, b), and Z(c, 0). Find the coordinates of W without using any new variables.Any help I could get on this one would be great! I don't understand this at all.

Answers

Answer 1
Answer:

Answer:

Co-ordinates of W must be (c+a,b).

Step-by-step explanation:

We are given that,

PVWZ is a parallelogram with vertices P(0,0), V(a,b) and Z(c,0).

Since, PVWZ is parallelogram.

The possible line segments are PV, VW, WZ and ZP.

Also, as the opposite sides must be parallel for the parallelogram, the co-ordinates will move accordingly.

So, we see from the figure that,

Co-ordinates of W must be (c+a,b).

Answer 2
Answer: Ill take (c,b) would be the answer


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Please help me on this

Answers

y+x=8\n y=8-x\n\n (12)/(x)=8-x\qquad x\not=0\n 12=8x-x^2\n x^2-8x+12=0\n x^2-8x+16-4=0\n (x-4)^2=4\n x-4=2 \vee x-4=-2\n x=6 \vee x=2\n\n y=8-6 \vee y=8-2\n y=2 \vee y=6\n \boxed{(x,y)=\{(2,6),(6,2)\}}

\displaystyle S_P=\int\limits_2^68-x-(12)/(x)\, dx\n S_P=\left[8x-(x^2)/(2)-12\ln x\right]_2^6\n S_P=8\cdot6-(6^2)/(2)-12\ln 6-(8\cdot2-(2^2)/(2)-12\ln 2)\n S_P=48-18-12\ln 6-16+2+12\ln2\n S_P=16-12\ln 6+12\ln 2\n S_P=16-12(\ln 6-\ln 2)\n\boxed{S_P=16-12\ln 3}

\displaystyle S_Q=\int\limits_2^6(12)/(x)\, dx\n S_Q=\left[12\ln x\right]_2^6\n S_Q=12\ln 6-12\ln 2\n S_Q=12(\ln6-\ln 2)\n \boxed{S_Q=12\ln 3}

\displaystyle V=\pi \int \limits_a^b f^2(x)\, dx\n\n V=\pi \int \limits_2^6 \left((12)/(x)\right)^2\, dx\n V=\pi \int \limits_2^6 (144)/(x^2)\, dx\n V=\pi\left[-(144)/(x)\right]_2^6\n V=\pi \cdot \left(-(144)/(6)-\left(-(144)/(2)\right)\right)\n V=\pi \cdot (-24+72)\n V=\pi \cdot48\n \boxed{V=48\pi}

Which algebraic expression is a polynomial with a degree of 5?3x5 + 8x4y2 – 9x3y3 – 6y5
2xy4 + 4x2y3 – 6x3y2 – 7x4
8y6 + y5 – 5xy3 + 7x2y2 – x3y – 6x4
–6xy5 + 5x2y3 – x3y2 + 2x2y3 – 3xy5

Answers

The degree of a polynomial is the highest exponent or sum of exponents of the variables in the individual terms of a polynomial.

Looking at each the polynomial:

3x5 + 8x4y2 – 9x3y3 – 6y5: Degree is 6 (look at the 2nd and 3rd term)

2xy4 + 4x2y3 – 6x3y2 – 7x4: Degree is 5 (look at 1st, 2nd, and 3rd term)

8y6 + y5 – 5xy3 + 7x2y2 – x3y – 6x4: Degree is 6 (look at 1st term)

–6xy5 + 5x2y3 – x3y2 + 2x2y3 – 3xy5: Degree is 6 (look at 1st and last term)

Therefore, the answer is the second option:
2xy4 + 4x2y3 – 6x3y2 – 7x4

Answer:

2xy^4 + 4x^2y^3 - 6x^3y^2 - 7x^4

Step-by-step explanation:

Since, the highest degree in a polynomial is called the degree of the polynomial,

While, the degree of each term in a polynomial with two variables is the sum of the exponents in each term.

In 3x^5 + 8x^4y^2 - 9x^3y^3 - 6y^5,

Sum of exponents are 5, 6, 6, 5,

So, degree of the polynomial is 6.

In 2xy^4 + 4x^2y^3 - 6x^3y^2 - 7x^4,

Sum of exponents are 5, 5, 5, 4,

So, degree of the polynomial is 5.

In 8y^6 + y^5 - 5xy^3 + 7x^2y^2 - x^3y - 6x^4,

Sum of exponents are 6, 5, 4, 4, 4, 4

So, degree of the polynomial is 6.

In -6xy^5 + 5x^2y^3 - x^3y^2 + 2x^2y^3 -3xy^5,

Sum of exponents are 6, 5, 5, 5, 5

So, degree of the polynomial is 6.

Jenna got 12,or 3/5, of her answers on the test right. How many questions were on the test?

Answers

20 because you set it up as a proportion. 3/5 12/? multiply 12 and 5 then divide by 3 to get 20

Twenty students in class A an 20 students in class B were asked how many hours they took prepare for a exam

Answers

what are you talking about

Write the equation in standard form 6x=y+3

Answers

The standard form of this equation is 6x - y = 3. Standard form is Ax + By = C, where A and B are the coefficients for x and y, and C is the number without a variable attached, or the constant. We just need to do a bit of algebra to get the equation in standard form.

6x = y + 3   Given
6x - y = 3   Subtract y from both sides

Hope this helps!
standard form  is ax+by=c
6x=y+3
lets move the y over to left side
minus y from both sides
6x-y=3
 

55%of what number is 22

Answers

55% of 40 is 22

Change the percentage into a decimal by dividing it over 100:

55/100 = 0.55

Divide:

22/0.55 = 40

% * whole = part

0.55 * x = 22

x=40

55% of 40 is 22