A soup can has a height of 4 inches and a diameter of 3 inches. Which of the following is the closest to the volume of the soup can?

Answers

Answer 1

Answer: 12...................

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3(2x + 1 ) = 2(x + 1) + 1

Answers

3(2x+1)=2(x+1)+1

Step 1:Simplify both sides of the equation

(3)(2x)+(3)(1)=(2)(x)+(2)(1)+ -(distribute)

6x+3=2x+2+1

6x+3=(2x)+(2+1) -(Combine Like Terms)

6x+3=2x+3

Step 2: Subtract 2x from both sides

6x+3-2x=2x+3-2x

4x+3-3=3-3

4x÷4=0÷4

x=0

The figure below is a regular octagon with a side length of 8 inches.8 inches
To the nearest square inch, what is the area of the figure?
309
118
64
49

Answers

Answer:

309in²

Step-by-step explanation:

Area of an octagon is expressed as;

A=2(1+√2)a²

a is the side length of the octagon

Given

a = 8

Substitute into the formula

A = 2(1+√2)(8)²

A = 2(1+√2)(64)

Expand

A = 2(64+64√2)

A = 128+128√2

A = 128+128(1.414)

A = 128+181.01

A = 309in²

Hence the area of the octagon is 309in²

A candy ore is building a display with two rectangular prisms.base of each prism is a square Theis 12 inches tall and the with edge length of 5 inches.oneother is twice as tall. The two prismsare stacked so pieces do not overlap.What is the total volume of the display?

Answers

since square base, legth=width=5

twice of 12=24 so the heighs are 12 and 24

V=LWH

V1=5*5*12=300
V2=5*5*24=600

total volume=300+600=900 in^3

Kyle ran 2/3 mi on Monday,1 1/6 mi on Tuesday, and 7/12 mi on Wednesday.How many total miles did Kyle run?

Express the answer in simplest form.

Answers

you would change the denominators to the least common multiple, in this case, 12. then you would change the fractions to 8/12, 14/12, and 7/12. you would add those, and get 29/12. divide 29 by 12, and get 2. add the rest to get 2 5/12.

$(2)/(3)+1 (1)/(6)+ (7)/(12) \n \n (2)/(3)+ 1 (1)/(6)= (2)/(3)+ (1*6+1)/(6)= (7)/(6)+ (2)/(3)= (2*2)/(3*2)= (4)/(6)+ (7)/(6)= (11)/(6)=1 (5)/(6) \n \n (7)/(12)+1 (5)/(6)= (11*2)/(6*2)= (22)/(12) + (7)/(12) = (29)/(12)=2 (5)/(12)$

One of the community service groups is going to plant a garden. 2/3 of the space will be used for vegetables. 1/4 of the vegetable space will be used for tomatos. what fraction of the garden will be used for tomatoes? draw a picture below.

Answers

Answer:

1/6 of the vegetables space will be used for the tomatoes

Answer:

1/12 of the Garden

Step-by-step explanation:

When adding fractions, the denominators need to be the exact same number. Therefore, you need to find the LCM. The LCM of 3 and 4 is 12, so all the denominators will be 12.

2/3 * 4/4 = 8/12

1/4 * 3/3 = 3/12

8/12 + 3/12 = 11/12

Now you need to subtract it from 1 (the garden).

12/12 - 11/12 = 1/12

The daily revenue from the sale of fried dough at a local street vendor in Boston is known to be normally distributed with a known standard deviation of $120. The revenue on each of the last 25 days is noted, and the average is computed as $550. A 95% confidence interval is constructed for the population mean revenue. If the data from the last 40 days had been used, then the resulting 95% confidence intervals would have been _____________________. Multiple Choice narrower, with a larger probability of reporting an incorrect interval wider, with the same probability of reporting an incorrect interval narrower, with the same probability of reporting an incorrect interval wider, with a larger probability of reporting an incorrect interval Next

Answers

Answer:

Narrower with the same probability of reporting an incorrect interval

Step-by-step explanation:

Increasing the sample size shrinks the width of the confidence interval because the larger the sample size, the more accurate the sample represents the true population.

Standard Error is calculated by multiplying the z or t score of the confidence level by the standard deviation, then dividing by the square root of the sample size

E = z(s)/√n

t scores are used for samples below a size of 30. All t values for 95% confidence are higher than the z score of 1.96, which is used when the sample is greater than 30. This causes a larger value for the error estimate, therefore creating a larger width for the confidence interval.

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