The slope and y-intercept of the given line are -3 and 9 respectively.
The general equation of a line in two variables of the first degree is represented as Ax + By +C = 0, A, B ≠ 0 where A, B and C are constants which belong to real numbers.
When we represent the equation geometrically, we always get a straight line.
Given that, an equation of a line y = -3x+9, we need to determine the slope and the y-intercept of this line,
The slope of a line tell about the steepness and the y-intercept tells the point where it intersects the y-axis,
The slope-intercept form of the equation of a line is given by ;
y = mx+c
Here, m is the slope and c is the y-intercept,
So, the given equation is y = -3x+9
Comparing with the slope-intercept form,
m = -3 and y-intercept = 9
Hence, the slope and y-intercept of the given line are -3 and 9 respectively.
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a. True
b. False
Answer:
It would be -3a
Step-by-step explanation:
(-6-4+7)a
Answer:
3. x = 5
4. -5 1/25
Step-by-step explanation:
-3x+5=-10
Subtract the 5 from both sides...
-3x = -15
Divide by -3
x = 5
For 4, it's just multiplying.
-2 4/5 in improper form is -14/5
1 4/5 in improper form is 9/5
-14/5 x 9/5 is -126/25
-126/25 can be -5.04 or -5 1/25.
Answer:
3. a (x=5)
4. -126/25
Step-by-step explanation:
3. -3x+5=-10
-3x=-10-5
-3x=-15
x=5
4. -(-2 4/5) x 1 4/5
(-14/5) x 9/5
= -126/25
Bx+Cy=D
Solve for y
the answer is 3 3/10
hope this helps
Answer:
The answer is 48
Step-by-step explanation: