Don randomly draws two cards from a standard deck of 52 cards. He does not replace the first card. What is the probability that both cards are aces?

Answers

Answer 1

Answer: easy
so remember
4 aces in a deck
probability =(desired outcomes)/(total possible)

total possible=52

4/52=1st card
then since he picked 1 out the total possible is and assuming he drwe an ace 3/51
so the answer is 4/52 times 3/51=1/221

Answer 2

Answer:

Answer: 1/221

Step-by-step explanation:

A P E X

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If T(n) = 6n + 2 what is the 3rd term

Answers

To find the 3rd term, just replace the 'n' with 3.

Therefore:

t(3) = 6(3) + 2
t(3) = 18 + 2
t(3) = 20.

The 3rd term is 20.

T(n)=6n+2 T3=6(3)+2 T3=20

If a roof's slope is 0.5, how high will the roof rise over a 17-foot run?a). 8 1/2 feet
b). 17feet
c). 1/34 feet
d). 34 feet

Answers

The answer to the mathematics question presented above would be letter a) 8 and 1/2 feet. If a roof's slope is 0.5, the height of the rise of the roof over a 17 foot run would be 8 and 1/2 feet. I got this answer through multiplying the slope and the run to get the rise.

Answer a) 8 and half feet.

You calculate it in this way

slope = rise / run ⇒ rise = slope * run = 0.5 * 17 feet = 8.5 feet.

In a class of 24 students, 25 percent of them failed a test. How many students failed a test

Answers

x/24 = 25/100
100x = 600
100x/100 = 600/100
x = 6
6 students failed the test

25 is 1/4 and 1/4 of 24 is 6 ( that is the easy way)

Complete answer choices

Answers

Answer:

Number one is B and E

Step-by-step explanation:

And 2 is C

If the area of a rectangle is 16s^2t and the length is 8st^2, what would be the width of the rectangle, given that width is found by dividing area by length? Simplify the answer.2st

2 over the quantity s times t

the quantity of 2 times s all over t

t over the quantity 2 times s

Answers

Given:
Area = 16s²t
Length = 8st²
Width = ?

Width = Area / Length
Width = 16s²t / 8st²
Width = 2s/t ⇒ the quantity of 2 times s all over t.

Answer:

$(2s)/(t)$

Step-by-step explanation:

The probabilities of a test are represented by I for infected; U, uninfected; D, infection detected; and N, no infection detected. What is the symbolic way to represent the probability of a true positive? P(I⋂D) P(I⋂D)P(D) P(U⋂N)P(N) P(I⋃D)