MATHEMATICS HIGH SCHOOL

Solve for a and b
(6a-3)=(7b-10)

Answers

Answer 1
Answer:

Answer:

for A=(7b-7)/(6) and for B=(6a+7)/(7)

Step-by-step explanation:

For A

\left(6a-3\right)=\left(7b-10\right)

6a-3+3=7b-10+3

6a=7b-7

(6a)/(6)=(7b)/(6)-(7)/(6)

a=(7b-7)/(6)

For B

\left(6a-3\right)=\left(7b-10\right)

7b-10=\left(6a-3\right)

7b-10=6a-3

7b-10+10=6a-3+10

7b=6a+7

(7b)/(7)=(6a)/(7)+(7)/(7)

b=(6a+7)/(7)

Related Questions

How do you multiply 5/12 times 2/9?
There are 3 times as many used bikes in the showroom as there as new bikes. There are 164 bikes total in the showroom. How many new bikes are in the showroom
If i created 6 inch by 6 inch square what would the area be
If a yield sign is a regular polygon what is the measure of each angle
What single decimal multiplier would you use to increase by 4% followed by a 3% increase

Perform the indicated operation.5/4 + 7/9

a.4/9
b. 2 4/9
c. 2 1/36

Answers

5/4 + 7/9 = 5*9/36 + 7*4/36 = 45/36 + 28/36 = 73/36 = 2 1/36
so
the answer is C

What percent of 45 is 72

Answers

45%of x=72
45/100 of x=72
9/20 of x=72
x=72*20/9
x=160..............

Answer:

1.6

Step-by-step explanation:

** If you your answer contains an irrational number (a never ending decimal number) leave the number under the square root symbol.

Answers

The answer is the square root of 23 i.

(The “i” is outside of the square root symbol, and the 23 is positive).

Hope this helps! (:

The data set below has a lower quartile of 13 and an upper quartile of 37.1, 12, 13, 15, 18, 20, 35, 37, 40, 78

Which statement is true about any outliers of the data set?

The data set does not have any outliers.

The lowest value, 1, is the only outlier.

The greatest value, 78, is the only outlier.

Both 1 and 78 are outliers.

Answers

Answer:

The correct option is 3.

Step-by-step explanation:

The first and third quartile of the data are 13 and 37.

The interquartile range is the difference between Q₃ and Q₁.

\text{Interquartile Range}=Q_3-Q_1

\text{Interquartile Range}=37-13=24

We have to find 1.5 (IQR),

1.5* \text{Interquartile Range}=1.5* 24=36

Now subtract 36 from Q₁ and add 36 in Q₃, if data lies outside the interval [Q₁-1.5(IQR),Q₃+1.5(IQR)] are called outliers.

Q_1-36=13-36=-23

Q_3+36=37+36=73

The outliers are the numbers which lies outside the range [-23,73]. Only 78 lies outside the range, therefore the correct option is 3.

Answer:

its C The greatest value, 78, is the only outlier

Step-by-step explanation:

The points (8,v) and (7,6) fall on a line with a slope of 10. What is the value of v?

Answers

Answer: v = 16

Step-by-step explanation:

     A slope of ten means that for every +1 increase in the x-coordinate, the y-coordinate increases by +10. Using this information, we can solve for v.

     We will add one to the x-value and add 10 to the y-value.

Given:

    (7, 6), m = 10

Use the slope:

    (7 + 1, 6 + 10) = (8, 16)

Answer:

    v = 16

The distance between two places is 120 km. A car travelling at a certain speed can cover the distance in 2 hours 30 minutes. By how many km/h should the speed of the car be increased for it to take 30 minutes less to cover the distance?Don't spam!!
Step by step explanation is needed..​

Answers

Answer:

Distance between two places=120 km

Step-by-step explanation:

 

Time= 2 hrs 30 min

       =(2*60)min+30min

       =120min+30min

       =150min=150/60 hr

        = 5/2 hr

Speed = distance /time

          = (120/5/2)km/hr

          =(120×2/5)km/hr

          =(240/5)km/hr

          = 48 km/hr

New time = 2 hr 30min-30min

               = 2hr

Distance =120km

Speed  = Distance /time

           =120/2 km/hr

           = 60 km/hr

Increase in speed=(60-48)km/hr  

                            =12km/hr

Another way to show :

Distance = 120km

speed=Distance/time

=120/2.5=48 km/hr

New speed=120/2=60 Km/hr

change inspeed=60-48=12km/hr
Other Questions
What are the coefficients in the polynomial 5x^2 + 2x - 4?A: 5, 2 B: -5, -2 C: 5, 2, -4 D: 5, -2, -4
Which equation finds the volume of a cube with a side length of 6n^6 units? a. (2n^6)^3 = 8n^16 cubic units b. (2n^6)^3 = 2n^18 cubic units c. 2(n^6)^3 = 2n^18 cubic units d. 2(n^6)^3 = 6n^18 cubic units
What is the LCM of 3 and 7? 3 7 14 21
How the expressions 27 and 2.7 alike