the perimeter of a basketball court is 102 meters, and length is 6 meters longer than twice the width, what r length and width. what is width _m.

Answers

Answer 1

Answer: Perimeter = 2(l + w)

Thus,

102 = 2(l + w)

l = 6 + 2w

102 = 2( 6 + 2w + w)
102 = 12 + 4w +2 w
102 = 12 + 6w
90 = 6w

Thus, w = 15.

Length = 6 + 2w
= 6 + 30
= 36.

Thus, the length is 36 meters and width is 15 meters.

Related Questions

Jack's mother gave him 50 chocolates to give to his friends at his birthday party. He gave 3 chocolates to each of his friends and still had 2 chocolates left. Write an equation to determine the number of friends (x) at Jack's party.
What number should be added to both sides of the equation to complete the square?x2 – 6x = 5
-4 (5x - 1)+ -11 (2x + 4)
The expression 15n + 2(3p) represents the amount Isaiah spent buying gasoline and snacks, where n represents the price of each gallon of gasoline and p represents the cost of each snack that he bought. Which statement is true about the amount Isaiah spent?
Write an inequality for the given statement: The sum of x and 25 is less than 75.

The amount of water in a bottle is reduced by 85% to 120 ml. How much water was originally in the bottle?

Answers

At first it was 100%. When it was reduced by 85%, it became 25%. The 25% represents 120 ml. So 100% would be (120/25) × 100 = 480 ml.

g(p)=(p-2 )and g(x)=(p^3+4p^2-2) evaluate g(p)*h(p) by modeling or by using the distributive property.

Answers

Given that g(p)=p-2 and

$h(p)=p^3+4p^2-2$

Now we have to evaluate g(p)*h(p) by modeling or by using the distributive property.

We know that g(p)*h(p) means just multiply expressions of g(p) with h(p)

which can be shown as following:

$g(p)*h(p)=(p^3+4p^2-2)(p-2)$

Apply distributive property

$g(p)*h(p)=p(p^3+4p^2-2)-2(p^3+4p^2-2)$

$g(p)*h(p)=p^4+4p^3-2p-2p^3-8p^2+4$

$g(p)*h(p)=p^4+2p^3-2p-8p^2+4$

$g(p)*h(p)=p^4+2p^3-8p^2-2p+4$

Hence final answer is $g(p)*h(p)=p^4+2p^3-8p^2-2p+4$

Six times the sum of a number and twelve is forty. Which equation represents this?

6N + 12N = 40
6N + 12 = 40
6(N + 12) = 40

Answers

Depends if number twelve is multiplied by six as well. In other words, it depends if the text means:
six times the sum of (a number and twelve) or six times the sum of a number and than plus 12 equal 40.

In first case answer is:
6(N + 12) = 40 and in second
in second:
6N + 12 = 40

The last one
6(N+12)= 40

A customers services representative earns $13 an hour and he works 24 hours a week . What is his weekly wage

Answers

The Answer is $312

Your welcome

well , this is common sense . multiply 24 hrs * 13$ and wallah magic you end up with 312$ a week.

Pyramid ABCDE is a square pyramid.

What is the lateral area of pyramid ABCDE ?

Answers

Answer:

A. $256√(3)\text{ in}^2$

Step-by-step explanation:

Please find the attachment.

We have been given an image of a square pyramid ABCDE. We are asked to find the lateral area of pyramid.

First of all we need to find the height of pyramid.

The lateral height of the pyramid will be the length of altitude drawn from the lateral face of pyramid to the base of pyramid.

Since the base of pyramid is square, so the length of segment CM will be half the length of BC that is 16.

Since tangent relates the opposite and adjacent sides of a right triangle, so we can find the lateral height as:

$\text{tan}=\frac{\text{Opposite}}{\text{Adjacent}}$

$\text{tan}(60^(\circ))=(AM)/(8)$

$√(3)=(AM)/(8)$

$√(3)* 8=(AM)/(8)* 8$

$8√(3)=AM$

$\text{Lateral surface area of pyramid}=(1)/(2)*pl$ , where,

p = Perimeter of the base,

l = Lateral or slant height.

$\text{Lateral surface area of pyramid}=(1)/(2)*4*16*8√(3)$

$\text{Lateral surface area of pyramid}=2*16*8√(3)$

$\text{Lateral surface area of pyramid}=256√(3)$

Therefore, the lateral surface area of our given pyramid is $256√(3)$ square inches and option A is the correct choice.

Answer:

256√3 in^2.

Step-by-step explanation:

tan 60 = lateral height of 1 face / 8

Lateral height = 8 tan 60 = 8√3

Area of 1 face = 8 * 8√3 = 64√3

Lateral Area = 4 * 64√3 = 256√3 in^2

Find the solutions to sin2(x) + cos(x) = 1, keeping 0 ≤ x < 2π

Answers

sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}

Answer:

Which statements did you include in your answer?

Isolate sin(x) by adding 4 and taking the square root of both sides.

State that sin(x) = 2 or sin(x) = –2.

State that –2 and 2 are undefined values of the inverse sine function.

There are no solutions because –2 and 2 are not in the domain of the function.

Step-by-step explanation:

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