What number should be added to both sides of the equation to complete the square?x2 – 6x = 5

Answers

Answer 1
Answer: take 1/2 of -6 and square it
-6/2=-3
(-3)^2=9
9 should be added
x^2-6+9=5+9
(x-3)^2=14


9 should be added
Answer 2
Answer:

To complete the square of the equation, the number to add to both sides is: 9.

How to Complete the Square of an Equation?

To complete the square of an equation, the number to add to both sides should be determined by squaring half of the term that has a variable without an exponent.

Given the equation, x² - 6x = 5:

To complete the square, square half of -6

1/2 of -6 = -3

Square of -3 = 9

Therefore, to complete the square of the equation, the number to add to both sides is: 9.

Learn more about square of an equation on:

brainly.com/question/24860429


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6.5 was added to a certain number. This sum was then divided by 13.6. Finally, the quotient was multiplied by 5. This product came out to 5. What was the number

Answers

Answer:

7.1

Step-by-step explanation:

Here's how we have to set this up.  We will start with the first statement, which algebraically looks like this:

x + 6.5 = y (since we don't know what x is, we don't know what the sum of x and 6.5 is.  We will call that new number y.)

Next, we are dividing that sum, y, by 13.6:

(y)/(13.6)=z (again, since we don't know what y is, we don't know what y divided by 13.6 is.  We will call that new number z.)

Finally, the quotient, z, is multiplied by 5:

5z

Now we work backwards, subbing in our unknowns, one at a time.  

5z

If z = (y)/(13.6), we sub it into the expression 5z:

5((y)/(13.6)) and

if y = x + 6.5 we plug that in for y:

5((x+6.5)/(13.6))=5 since we know that whole mess is equal to 5.  NOw we solve for x, the original number.  Begin by dividing both sides by 5 to get:

(x+6.5)/(13.6)=1

Now multiply both sides by 13.6 to get:

x + 6.5 = 13.6 so

x = 7.1

Check this if you'd like by plugging in the 7.1 for x in the intial equation to solve for y, then plug that into the next equation to solve for z, then see if they're equal (they are, but test it out for yourself).

PLEASE HELP ME :) 20 points

Answers

Answer:

its d thats the right anwsers

Step-by-step explanation:

The park is 6 mi due east of Freeport High School, and the library is 4 mi due west of the school. The police department is located due north of the school and is 5 mi from the library.How far is the police department from the park? Round to the nearest tenth of a mile.


blank mi

Answers

The answer is 6.7 mi.

Since the right triangle is present, to calculate this we will use the Pythagorean theorem. According to the Pythagorean theorem, the square of the hypotenuse (c²) is equal to the sum of the squares of two other sides (a² + b²):
c
² = a² + b²

First, we need to express symbols:
b - side of the right triangle (distance 
between police department and Freeport High School).
a1 - 
side of the first right triangle (distance between library and Freeport High School).
a2 - 
side of the second right triangle (distance between park and Freeport High School).
c1 - hypotenuse of the first triangle (distance between 
police department and library).
c2 - 
hypotenuse of the second triangle (distance between police department and park).

Therefore, we need to calculate c2.
It is given:
a2 = 6 mi
a1 = 4 mi
c1 = 5 mi

First, let's calculate b, which is a common side for two triangles:
c1² = a1² + b²
b² = c1² - a1²
b² = 5² - 4²
b² = 25 - 16
b² = 9
√b² = √9
b = 3.

We know b, now we can calculate c2:
c2² = a2² + b²
c2² = 6² + 3²
c2² = 36 + 9
c2² = 45
√c2² = √45
c2 = 6.7

The distance between police department and park is 6.7 miles.

Solve for n

-53+n=-28

Answers

-53+n=-28
n= -28+53
n= 25
Hope this helps you!! =')
Have a good days ..................

8+4i
———
2i

please show work!!

Answers

Please brainliest this what Siri said

Which of the following are useful ways of finding the value of a variable? Check all that applyA.Writing an equation
B.Drawing a graph
C.Reading a table
D.Drawing a diagram

Answers

Writing an equation and Drawing a graph are two ways or useful ways of finding the value of the variable. These two are the basic ways of solving the given variable equation. In mathematical ways, this is the most useful ways.
Drawing a graph as it shows the change in variables.