9/16 + 1/2 equals what

Answers

Answer 1

Answer: 1 / 2 = ( 1 * 8 ) / ( 2 * 8 ) = 8 / 16 ;
9 / 16 + 8 / 16 = ( 9 + 8 ) / 16 = 17 / 16 ;

Answer 2

Answer: 9 /16 + 1/2 =?
9 /16 = 0. 5625
1/2 = 0.5
therefore , 9/ 16 +1 / 2 = 0.5625 + 0.5
= 1 .0625

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Write a compound inequality that represents the situation. On a road in the city of Rochester, the maximum speed is 50 miles per hour, and the minimum speed is 20 miles per hour.A. 20 ≥ x ≥ 50 B. 20 < x < 50 C. 20 > x > 50 D. 20 ≤ x ≤ 50
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Determine if the system has one solution, infinitely many solutions, or no solution. x=-7y+34 x+7y=32
A new restaurant is having advertising flyers printed. The cost to design and lay out the flyer is $300. There is an additional cost of $0.12 per flyer printed. Identify the fixed cost and the variable cost of the partial variation. (2 marks)Fixed cost (b) = _________ Variable cost (m) = ___________Write the equation representing this relationship in the form y=mx+b.(1 mark)c)Use your equation in (b) to determine the total cost of 300 flyers. (2 marks)

What is 64x6 + 27 written as a sum of cubes?(4x)3 + 33
(4x2)3 + 33
(4x2)3 + 93
(4x3)3 + 33

Answers

64x^6 + 27

sum of cubes:
64 = ∛64 = 4
x^6 = (x²)³
27 = ∛27 = 3

(4x²)³ + 3³ 2nd option

Answer:

option B

Step-by-step explanation:

edge 2023

Need help DUE IN 50 mins

Answers

The value of x is 8 and the value of y is 21.

The given lines $l$ and $m$ are parallel to each other. Thus,

Angles, $(7x+12)^o$ and $(12x-28)^o$ are equal due to absolutely none angles.

$7x+12=12x-28\n5x=40\nx=8$

The sum of the angles $(12x-28)^o$ and $(9y-77)^o$ is equal to $180^o$ .

$(12x-28+9y-77)=180\n12*8-28+9y-77=180\ny =21$

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What is the solution to the system of equations?6x – 9y = 16
2x – 3y = 7
A) (5, 1)
B) (2, -1)
C) (3, 2/9)
D) no solution

Answers

If you would like to know the solution to the system of equations, you can calculate this using the following steps:

6x – 9y = 16
2x – 3y = 7 /*(-3) ... -6x + 9y = - 21
___________
6x – 9y - 6x + 9y = 16 - 21
0 = - 5

The correct result would be D) no solution.

Josh spent $30 at the movies. 1/5 was spent on a drink, 45% on a ticket and the rest on food. How much did he spend on food?

Answers

Answer:

$10.5

Step-by-step explanation:

Given data

Total amount=$30

Drink = 1/5*30= $6

Ticket= 45% of 30

=45/100*30

=0.45*30

=$13.5

The remainder is for food

=30-6-13.5

=$10.5

the student council is organizing a trip to a rock concert. all proceeds from ticket sales will be donated to a charity. tickets to the concert cost $31.25 per person if a minimum of 104 people attend. for every 8 extra people that attend, the price will decrease by $1.25 per person.a). how many tickets need to be sold to maximize the donation to charity?b). what is the price of each ticket that maximizes the donation?c). what is the maximum donation?

Answers

I got the maximum donation $152

Final answer:

To maximize the donation to charity, a total of 117 tickets need to be sold. The price per ticket that maximizes the donation is $29.0625. The maximum donation is $3,400.3125.

Explanation:

To maximize the donation to charity, we need to determine the number of tickets that need to be sold and the price per ticket that will result in the maximum donation.

a) To find the number of tickets, we can start with the minimum attendance requirement of 104 people. For every 8 extra people that attend, the price decreases by $1.25. So the number of extra people is calculated by dividing the total increase in price ($31.25 - $30) by the decrease per person ($1.25), which is 8. Therefore, the number of extra people is 13. To find the total number of tickets, we add the minimum attendance of 104 people and the number of extra people of 13. So the total number of tickets that need to be sold to maximize the donation to charity is 117.

b) To find the price per ticket, we start with the price of $31.25 and take into account the decrease of $1.25 for every 8 extra people. We can calculate the price decrease per person by dividing $1.25 by 8, which is $0.15625. To find the price per ticket, we subtract the decrease per person from the initial price, multiplied by the number of extra people. So the price per ticket that maximizes the donation is $31.25 - ($0.15625 × 13) = $29.0625.

c) To find the maximum donation, we multiply the price per ticket by the total number of tickets sold. So the maximum donation is $29.0625 × 117 = $3,400.3125.

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Part B: The area of a rectangle is (81x2 − 4y2) square units. Determine the dimensions of the rectangle by factoring the area expression completely. Show your work. (5 points)

Answers

The dimensions of the rectangle are 9x + 2y units and 9x - 2y units.

What is the area of the rectangle?

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

To determine the dimensions of the rectangle, we need to factor the area expression completely. We can use the difference of squares formula to do this. The formula is:

a2 - b2 = (a + b)(a - b)

We are given that;

Area of rectangle= (81x2 − 4y2) square units.

Now,

We can identify that 81x2 and 4y2 are both perfect squares. The square roots of them are 9x and 2y respectively. So we can rewrite the area expression as:

81x2 - 4y2 = (9x)2 - (2y)2

Using the difference of squares formula, we can factor this expression as:

(9x)2 - (2y)2 = (9x + 2y)(9x - 2y)

We can check this by multiplying them and getting back the original area expression.

(9x + 2y)(9x - 2y) = 81x2 - 18xy + 18xy - 4y2 (9x + 2y)(9x - 2y) = 81x2 - 4y2

Therefore, by the given area the answer will be 9x + 2y units and 9x - 2y units.

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Hello,

if the aim is to factorise:
81x²-4y²=(9x)²-(2y)²=(9x-2y)(9x+2y)

But the sides may also be and an other expression....

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Lyra and Donna are testing the two-way radios they built for their high school science project. Lyra goes to the top of a building that is 22 meters high with one of the radios and stands directly above the building’s entrance. Donna walks out of the entrance, perpendicular to the building, with the other radio. If Donna is more than 50 meters from the entrance, the connection between the radios breaks. What is the range of communication for the two radios to the nearest meter?