What is the disadvantages of using a credit card
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Amir owns and operates a clothing store. He sells a shirt for $59.95. He Originally bought the shirt for $40.50. What is the buying price as a percent of his selling price?
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a piece of licorice is to be cut into 10 equal size pieces. if the length of the piece of licorice is 2/3 yard, how long will each piece of licorice be?
IAcellusFind the volume of the cone.5Diameter: 14 m, Slant Height: 25 mHelp ResourcesRound to the nearest whole number.Volume[?] m3
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Answer:
(- 2, 4 )
Step-by-step explanation:
The equation of a line in point- slope form is
y - b = m(x - a)
where m is the slope and (a, b) a point on the line
y - 4 = - 3(x + 2) ← is in point- slope form
with (a, b ) = (- 2, 4 )
5(4 – 2) = 20 – 10
5 + (4 – 2) = 9 + 3
5(4 – 2) = 9 – 7
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Answer:
This is a genuine statement of you look real closely at it.
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a 2 = a 1 * r
8 = - 4 * r
r = 8 : ( - 4 )
r = - 2
a n = a 1 * r^(n-1)
a 5 = - 4 * ( - 2 ) ^4 = - 4 * 16 = - 64
Answer:
The fifth term in the sequence is - 64.
Answer:
B. an = –4 · (–2)n–1; –64
Step-by-step explanation:
b. {2,2,4}
c. (1,2, sqrt of 3 wouldn't it be B because it has all even numbers?
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The only set of numbers that could be the sides of a right triangle is **(b) {2, 2, 4}**.
The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
Therefore, in order for a set of numbers to be the sides of a right triangle, the following equation must hold:
hypotenuse^2 = leg1^2 + leg2^2
Let's check each of the given sets:
(a) {2, 3, √13}
hypotenuse^2 = √13^2 = 13
leg1^2 = 2^2 = 4
leg2^2 = 3^2 = 9
13 ≠ 4 + 9
Therefore, {2, 3, √13} cannot be the sides of a right triangle.
(b) {2, 2, 4}
hypotenuse^2 = 4^2 = 16
leg1^2 = 2^2 = 4
leg2^2 = 2^2 = 4
16 = 4 + 4
Therefore, {2, 2, 4} can be the sides of a right triangle.
(c) {1, 2, √3}
hypotenuse^2 = √3^2 = 3
leg1^2 = 1^2 = 1
leg2^2 = 2^2 = 4
3 ≠ 1 + 4
Therefore, {1, 2, √3} cannot be the sides of a right triangle.
Therefore, the only set of numbers that could be the sides of a right triangle is **(b) {2, 2, 4}**.
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Final answer:
The set of numbers that could be the sides of a right triangle is {2,3, sqrt of 13}.
Explanation:
To determine whether a set of numbers could be the sides of a right triangle, we can use the Pythagorean theorem, which states that the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides.
Let's check each set of numbers:
a. {2,3,√13}
b. {2,2,4}
c. (1,2,√3)
For set a, the sum of the squares of 2 and 3 is 13, which is equal to the square of √13. Therefore, set a could be the sides of a right triangle.
For set b, the sum of the squares of 2 and 2 is 8, which is not equal to the square of 4. Therefore, set b could not be the sides of a right triangle.
For set c, the sum of the squares of 1 and 2 is 5, which is not equal to the square of √3. Therefore, set c could not be the sides of a right triangle.
Therefore, the set of numbers that could be the sides of a right triangle is a. {2,3,√13}.
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-3m - n
3m - n
-3m - 3n
3m - 3n
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2m - n + (m - 2n)
2m - n + m - 2n
2m + m - n - 2n
3m - 3n
Answer is D.
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Let's first find the distance between points A and B:
Distance AB = √[(x2 - x1)^2 + (y2 - y1)^2]
Distance AB = √[(-5 - 1)^2 + (2 - (-2))^2]
Distance AB = √[(-6)^2 + (4)^2]
Distance AB = √[36 + 16]
Distance AB = √52 ≈ 7.21 (rounded to 2 decimal places)
Next, let's find the distance between points B and C:
Distance BC = √[(x2 - x1)^2 + (y2 - y1)^2]
Distance BC = √[(2 - (-5))^2 + (6 - 2)^2]
Distance BC = √[(7)^2 + (4)^2]
Distance BC = √[49 + 16]
Distance BC = √65 ≈ 8.06 (rounded to 2 decimal places)
Finally, let's find the distance between points C and A:
Distance CA = √[(x2 - x1)^2 + (y2 - y1)^2]
Distance CA = √[(1 - 2)^2 + (-2 - 6)^2]
Distance CA = √[(-1)^2 + (-8)^2]
Distance CA = √[1 + 64]
Distance CA = √65 ≈ 8.06 (rounded to 2 decimal places)
Since the isosceles triangle has two sides with the same length, the length of these sides is approximately 8.06 units (rounded to 2 decimal places).
To find the coordinates of the point where the line 2x + y = 11 crosses the x-axis, we need to set y to 0 and solve for x.
When y = 0, the equation becomes:
2x + 0 = 11
Now, isolate x:
2x = 11
x = 11 / 2
x = 5.5
So, the point where the line crosses the x-axis has coordinates (5.5, 0).