How many moles of atoms are in 9.00 g of 13c?

The molar mass of the compound is found by finding the empirical and

molecular formula of the compound.

• The molar mass of the compound, MM = 2 × 97 g/mol = 194 g/mol

Reasons:

Molar mass of CO₂ = 44.01 g/mol

Number of moles of CO₂ produced = ≈ 0.412 moles

Number of moles of produced C = 0.412 moles

Mass of C = 12 × 0.412 = 4.944 g

Molar mass of H₂O = 18.015 g/mol

Moles of H₂O produced = = 0.2575 moles

• Moles of produced H = 2 × 0.2575 = 0.515 moles

• Mass of H = 1.00784 × 0.515 ≈ 0.519 g

Molar mass of N₂ = 28.0134 g/mol

• Moles of N produced = 2 × = 2 × 0.103 = 0.206 moles

Mass of oxygen = 10 - 4.944 - 2.885 - 0.519 = 1.652

• Moles of oxygen, O = ≈ 0.103 moles

Therefore, we get;

Number of moles of produced C = 0.412 moles

Number of moles of produced H = 0.515 moles

Number of moles of oxygen, O ≈ 0.103 moles

Number of moles of N produced = 0.206 moles

Dividing by 0.103 gives;

• Mole ratio of C =

• Mole ratio of H =

• Mole ratio of O = 1

• Mole ratio of N =

• The empirical formula of the compound is therefore; C₄H₅N₂O

• The general molecular formula is of the form (C₄H₅N₂O)ₙ

Molar mass of the compound is between 150 g/mol and 210 g/mol (given)

The molar mass of C₄H₅N₂O = 4×12 + 5×1.00784 + 2×14 + 16 ≈ 97

The molar mass of C₄H₅N₂O ≈ 97 g/mol

Molar mass of the compound is between 150 and 210 g/mol, therefore, n in

(C₄H₅N₂O)ₙ = 2, which gives;

• The molar mass of the compound, MM = 2 × 97 g/mol = 194 g/mol

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Answer:

194 g/mol.

Explanation:

Hello,

In this case, one first must compute the mass of each element as shown below:

Next, the corresponding moles:

Then, each element's subscripts is found to be:

Therefore, the empirical formula is:

Nonetheless, it has a molar mass of 97bg/mol, thereby, by multiplying such formula by 2 one gets:

Which has a molar mass of 194 g/mol being correctly contained in the given interval.

Best regards.

Answer:

1-pentanol

Explanation:

Hexane is non-polar in nature. This is due to :

The bond in the molecule is C-H, which is non-polar in nature because the carbon and the hydrogen having very similar electronegativity values.

Hexane is also symmetric.

The intermolecular force acting in the molecule of the hexane are induced the dipole-dipole forces or London Dispersion forces / van der Waals forces which is a very weak force.

On the other hand, in the case of 1-pentanol, hydrogen bonding exist which is a strong intermolecular force.

Hence, more amount of thermal energy is required to boil 1-pentanol. hence, it has more boiling point.

Final answer:

The boiling point of 1-Pentanol is higher than hexane because it has stronger intermolecular forces caused by hydrogen bonding. Hexane, on the other hand, has weaker van der Waals forces.

Explanation:

The boiling point of a substance is determined by its intermolecular forces. 1-pentanol has a higher boiling point than hexane because of the presence of hydrogen bonding in 1-pentanol, which is a stronger intermolecular force than the van der Waals forces present in hexane. Hence, more energy is required to break the intermolecular forces in 1-pentanol making its boiling point higher.

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Answer:

a. endothermic reaction

Explanation:

In an endothermic reaction, heat is absorbed from the environment. This leaves the surrounding at a colder temperature compared to the system.

ΔH, the change in enthalpy is assigned a positive sign because the heat energy level of the final state is higher than that of the initial state.

Some examples are mostly dissolution substances in water.

Final answer:

The given reaction will shift towards cis-2-butene once placed in equilibrium. This can be determined by calculating the reaction quotient and comparing it with the equilibrium constant.

Explanation:

The reaction could either shift towards the cis-2-butene or trans-2-butene depending on whether the reaction quotient, Q, is lesser or greater than the equilibrium constant, Kp.

Bear in mind that Kp = Ptrans/Pcis. Let's say that Pt is the partial pressure of trans-2-butene and Pc is the partial pressure of cis-2-butene at equilibrium. If we start with 5 atm of each gas, the change in Pc is -x and the change in Pt is +x.

So, Kp = (5+x)/(5-x). We are given that Kp = 3.4. Solving these two equations will show that x is a negative value, which means that the system shifts towards cis-2-butene.

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Final answer:

For the isomerization reaction cis-2-butene ⇌ trans-2-butene, with an initial pressure of 5.00 atm for both gases and a Kp of 3.40, the system will shift towards the product, trans-2-butene, as Kp > Qp (1). This reflects the principle that a chemical system at equilibrium will shift to counteract any change.

Explanation:

In terms of the equilibrium constant (K), for gas-phase reactions, Kp represents equilibrium in terms of partial pressures, while Kc represents it in molar concentrations. For instance, in the isomerization reaction given cis-2-butene ⇌ trans-2-butene, Kp is given as 3.40. To determine the behavior of the system, we need to compare it to reaction quotient (Q). Given that the flask initially contains 5.00 atm of each gas, Qp is 1 (since Qp = partial pressure of trans-2-butene / partial pressure of cis-2-butene). Since Kp > Qp, the reaction will shift towards the products, hence the system will shift towards trans-2-butene. From this, it is clear that the equilibrium constant and reaction quotient play vital roles in determining the direction of shift in a chemical equilibrium.

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