The fraction of students in the class who are men can be calculated by dividing the number of men by the total number of students in the class. Given that there are 18 men in a class of 32 students, the fraction of men in the class is 9/16.
This question is dealing with the concept of fractions in mathematics. From the information given, we know that there are 32 students in the class and 18 out of those are men. To find the fraction of the class that is men, we divide the number of men by the total number of students in the class. This can be expressed as follows:
Number of men / Total number of students = Fraction of the class that are men.
By substituting the given figures into the formula we get:
18 / 32 = 9/16.
Therefore, 9/16 of the students in the class are men. This fraction can be further simplified by dividing both the numerator and denominator by the greatest common divisor.
#SPJ2
x - 5y = 15 2x + y = 12
c) 3x - 4y = 22
2x + 5y = 7
Answer
y=-4x-1
Step-by-step explanation:
Part A: Identify a coefficient, a variable, and a constant in this expression. (3 points)
Part B: If Javier works for 5 days and installs 48 windows, how much does he earn? Show your work to receive full credit. (4 points)
Part C: If Javier gets an increase in his stipend and receives $40 for snacks, would the coefficient, variable, or constant in the equation change? Why? (3 points)
Answer: 24) C. SSS only
26) D. DH = HF
Step-by-step explanation:
24.
Statement Reason
1. BD = CA 1. Given
2. AB = CD 2. Given
3. AD = AD 3. Reflexive Property
4. ΔABD = ΔDCA 4. SSS Congruency Theorem
We have no information about the angles so cannot use SAS Theorem.
26. G H F
E H D
Line up the letters to find the congruent sides:
⇒ GH = EH
HF = HD
GF = ED
Answer:
memers will always dance
Step-by-step explanation:
cosx cosy = 1/2 [cos(x+y) + cos(x−y)]