MATHEMATICS HIGH SCHOOL

A lizard needs to stay a safe distance from a cactus. The diameter of the cactus is 12 inches. If the lizard is 8 inches from a point of tangency, find the direct distance between the lizard and the cactus (x). If necessary, round to the hundredths place.

Answers

Answer 1

Answer:

Answer:

10 in

Step-by-step explanation:

We are given that

Diameter of cactus=d=12 in

Radius of cactus= $(d)/(2)=(12)/(2)=6 in$

Distance of lizard from point of tangency=8 in

We have to find the direct distance between lizard and cactus.

In triangle OAB,

OA=6 in

AB=8 in

Pythagorous theorem: $(Hypotenuse)^2=(base)^2+(perpendicular\;side)^2$

Using pythagorous theorem

$OB^2=(6)^2+(8)^2=100$

$OB=√(100)=10 in$

Hence, the direct distance of lizard from cactus=10 in

Answer 2

Answer: the answer should be 6 if i am right

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Answers

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Or
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Which is greater 1/9 or 1/8

Answers

1/8 is greater than 1/9 , because 1 is being divided by a smaller number and hence the result would be bigger than when that same 1 is divided by a bigger number as 9.

OR

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OR

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Answers

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Answers

Answer:

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Step-by-step explanation:

12x=70-14=56

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Answers

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Answers

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