The length of the shortest side of the triangle is 10cm.
It is given that congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side, the perimeter of the triangle is the same as the perimeter of a square whose side length is 2 units shorter than the length of the shortest side of the triangle.
All three corresponding sides are equal and all the three corresponding angles are equal in measure.
Let's have the variable x be the length of the shortest side.
To equate to demonstrate this problem:
Longer sides of the triangle is (1+x)
Perimeter = (x-2)*4
Therefore, the equation is 4(x-2)=(1+x)+(1+x)+x
Simplify:
4x-8=2+3x
4x=10+3x
x=10
So, the length of the shortest side of the triangle is 10cm.
Learn more about congruent triangle here:
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B. 19.6 square feet
C. 42.8 square feet
D. 78.6 square feet
Answer:
I did the test the answer is 19.6 square feet
Step-by-step explanation:
Answer:
3.7125
Step-by-step explanation:
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