B. solute
C. solution
D. solvent
Answer:
B. Solute
Explanation:
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b. light bulb
c. hair dryer
d. all of these are resistors
a) Kinetic energy of ball is 450J.
A 1kg ball is thrown into the air with an initial velocity of 30m/s. Newtonian physics says thekinetic energy that the ball have is:
( ×1 kg×= 450 J.
In physics, what is kinetic energy?
The energy a thing has as a result of motion is known as kinetic energy. A force must be applied to a thing in order to accelerate it. We must put forth effort in order to apply a force. After the job is finished, energy is transferred to the thing, which then moves at a new, constant speed.
b) Potential energy of ball is 450J
The whole amount of energy will be in the form of potential energy since the ball's kinetic energy will be equal to zero. As a result, when the ball reaches the peak of its climb, its potential energy will be 450 J.
c) 45m high into the air ball travel.
KE at start = GPE at the peak
450 = mgh
450 = (1)(g)(h)
450= (1)(10)(h)
45=h
Therefore, the ball will reach up to a height of 45m.
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Answer:
0.25 m
Explanation:
The intensity of the magnetic field around a current-carrying wire is given by:
where
where
is the permeabilty of free space
I is the current
r is the distance from the wire
In this problem, we know:
is the magnetic field
is the current in the wire
Re-arranging the equation, we can find the distance of the field from the wire:
It will take a car, 2.59 s to accelerate from 15.2 to 23.5 m/s.
speed is described as. the pace at which an object's location changes in any direction. Speed is defined as the distance traveled divided by the travel time. Speed is a scalar quantity because it just has a direction and no magnitude.
Given, the car has an average acceleration of 3.2 m/s².
To solve this problem, we can use the following kinematic equation:
v = u +at
where:
v is the final velocity (23.5 m/s)
u is the initial velocity (15.2 m/s)
a is the acceleration (3.2 m/s^2)
t is the time
We can rearrange this equation to solve for t:
t = (v -u)/a
substituting the values we have:
t = (23.5 - 15.2 ) / 3.2
t = 2.59375 seconds
Therefore, it will take approximately 2.59 seconds for the car to accelerate from 15.2 m/s to 23.5 m/s with an average acceleration of 3.2 m/s².
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Hello!
How long will it take a car to accelerate from 15.2 m/s to 23.5 m/s if the car has an average acceleration of 3.2 m/s² ?
We have the following data:
Vf (final velocity) = 23.5 m/s
Vi (initial velocity) = 15.2 m/s
ΔV (speed interval) = Vf - Vi → ΔV = 23.5 - 15.2 → ΔV = 8.3 m/s
ΔT (time interval) = ? (in s)
a (average acceleration) = 3.2 m/s²
Formula:
Solving:
Answer:
The car will take approximately 2.6 seconds to accelerate
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