A device has power -2 D . The device is a.A convex lens of focal length 50 cm
b.A concave lens of focal length 50 cm
c.A convex lens of focal length 2 m
d.A concave lens of focal length 2 m

Answers

Answer 1
Answer:

Answer:

b.

Explanation:

-vesign shows the lens is CONCAVE

f=1/power


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Electromagnetic waves can transfer energy without which of the following?A. Medium. B. Electric field. C. Magnetic field. D. Change in either a magnetic or an electric field.
Freddie Mercury is the singer of which Band Yes or Queen or Fleetwood Mac

All of the following are reasons that psychologists use a systematic method to conduct research except __________.

Answers

Answer: To help eliminate subjectivity

Explanation:

Edgenuity 2020

If sediment is pushed along the underside of a glacier, what would occur?

Answers

When sediment is pushed along the underside of the glacier, striations occur. Striations are "Scratches" that look like long, parallel grooves. This also shows the direction that the glacier has moved in. Sediment gets pushed along the underside due to the flowing of the glacier.

Answer:

Glacial Striations

Explanation:

Glacier is an erosion agent that transports and deposits sediments.

Due to the weight and gradual flow of a glacier, it carves along parts of the mass beneath it, these parts are known as sediments, this movement causes marks to appear on the land beneath it. These marks are called Glacial Striations.  

In a compressional wave the denser the medium is at the compressions the smaller is amplitude?

Answers

Wellll, let me think about that ...

I don't think I'd agree that you can characterize the amplitude of
a wave according to the density at only one point in it.  After all ...
a tiny wave in steel would be much denser at a compression than
a huge wave in air would be.

The amplitude of any wave is described as the difference between
a peak and the resting value.  Or even better ... half of the difference
between a maximum and a minimum.

So if you're looking at a longitudinal wave, like sound, I'd say if you
want to describe its amplitude, then you have to look at the density
at two points ... either the difference between the compression and
the resting densities, or the difference between the greatest compression
and the greatest rarefaction. 

That's my opinion.  I could be wrong.

The speed of sound waves through two different media, steel and air, was recorded. According to the graph, sound waves travel. A) through steel, but not through air
B) faster through steel than through air
C) faster through air than through steel
D) through steel and air at similar speeds

Answers

Answer: The correct answer is Option B.

Explanation:

Sound waves are a type of longitudinal waves. These waves are the waves in which particles of the medium travel in the direction of the wave. These waves require a medium to travel.

Sound waves travel faster in solids than in the gaseous medium because the particles in solid state lie close to each other and the vibrations of the sound waves travel faster when the particles lie closer to each other.

Hence, the correct answer is Option B.

Faster through steel than through air, B.

How does carbon dioxide affect the atmosphere

Answers

Explanation:

Carbon dioxide is a naturally occurring greenhouse gas... An increase in the amount of carbon dioxide creates an overabundance of greenhouse gases that trap additional heat. This trapped heat leads to melting ice caps and rising ocean levels, which cause flooding.

The average distance from the sun to Pluto is approximately 6.10 time 10^9 km. How long does it take light from the sun (384,000 km/s) to reach Pluto?

Answers


From the information as given in the question, the transit time
for light from the sun would be

       (6.1 x 10⁹ km) / (3.84 x 10³ km/sec) = 15,885 seconds (rounded).
                                                                       (4.4 hours) .
==============================

-- A better figure for Pluto's average distance from the sun is  5.874 x 10⁹ km.

-- " 384,000 km/sec " is about 28% too high for the speed of light.
    A much better figure is  300,000 km/sec.

Using these numbers, the transit time is

           (5.874 x 10⁹ km) / (3 x 10⁵ km/sec)  =  19,580 seconds
                                                                             (5.4 hours)