Earths inner core is
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What part of a wave best describes lowest point of a wave?A. the crest point B. the wavelength C. the center point D. the trough point
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Calculate the displacement for an object traveling at a constant velocity of 32 m/s for 4 s.
A snail travels at a rate of 2.37 feet per minute. a. Write a rule to describe the function. b. How far will the snail travel in 6 minutes?
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Answer:
Explanation:
Given:
d=12.5in=0.3175m
r=d/2=0.3175/2=0.15875m
ωf=75rev/min=7.85rad/s
t=3.80s
The angular acceleration
Tangential acceleration
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Answer:
60J
Explanation:
friction is the opposition to the motion of an object. Before a body can be set in motion, part of the energy or work-done must be used to overcome friction.
While kinetic energy is the energy associated with a body due to its motion.
Since friction tends to oppose the motion of a body,when a body start to move, some of the energy applied to the body to cause its motion is converted to heat due to friction.
Hence if a work-done of 100J is applied to a body that requires 40J of the work to overcome friction, the total change in the kinetic energy can be expressed as
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We have to be a little careful working with this question. Do you mean
that current is "constant" or do you mean it's "the same current" ?
-- If the energy source for the circuit is supplying DC ... like a battery
or a solar cell ... then the current is 'constant' at every point in the
circuit. It's not changing. It's the same now as it was 10 seconds
ago. But it's NOT necessarily the same amount of current everywhere
in the circuit.
-- If the energy source for the circuit is not supplying DC ... if it's an
AC generator, or a charged capacitor, or a function generator ...
then wherever you look in the circuit, the current is constantly
changing its value at that point.
-- And if there's any place in the circuit where there are components
connected in parallel, then the current must have different values
at different points in the circuit.
It can't be the same current everywhere.
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V=IR
In the question, the following values are given:
V = 4.5
I = 0.75
Substitute the values into the equation to find R, the resistance:
V = IR
4.5 = 0.75R
R = 4.5 / 0.75
R = 6 ohms
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mass (m) = 0.120kginitial velocity (Vo) = 0distance traveled (s) = 1.25 m
We first calculate for the final velocity of the ball:
Vf^2 = 2gs + Vo^2
Vf^2 = 2(9.8m/s2)(1.25m)
Vf = 4.95 m/s
Impulse = m(Vf−Vo)
Impulse = 0.120(4.95)
Impulse = 0.59 Ns
To find the momentum of the ball before it hit the floor, we need to figure out its final velocity using kinematics.
Values we know:
acceleration(a) - 9.81m/s^2 [down]
initial velocity(vi) - 0m/s
distance(d) - 1.25m [down]
This equation can be used to find final velocity:
Vf^2 = Vi^2 + 2ad
Vf^2 = (0)^2 + (2)(-9.81)(-1.25)
Vf^2 = 24.525
Vf = 4.95m/s [down]
Now we need to find the velocity the ball leaves the floor at using the same kinematics concept.
What we know:
a = 9.81m/s^2 [down]
d = 0.600m [up]
vf = 0m/s
Vf^2 = Vi^2 + 2ad
0^2 = Vi^2 + 2(-9.81)(0.6)
0 = Vi^2 + -11.772
Vi^2 = 11.772
Vi = 3.43m/s [up]
Now to find impulse given to the ball by the floor we find the change in momentum.
Impulse = Momentum final - momentum initial
Impulse = (0.120)(3.43) - (0.120)(-4.95)
Impulse = 1.01kgm/s [up]