distance decreases the force between objects. TRUE or FLASE
Explanation:
TRUE
the answer is true. Trust me. Im an expert at this.
Decomposition
Combustion
Single Replacement
Answer:
Decomposition= one-reactant
Combustion= 2-reactants
Single displacement= 2-reactant
Explanation:
i. Accuracy
ii. Precision
b. A known amount of analyte is added to an aliquot of the sample and analyzed with sample.
i. Accuracy
ii. Precision
c. Aliquots from a blood sample are sent to three separate laboratories for analysis using the same method.
i. Accuracy
ii. Precision
d. Identical standard are analyzed by two different methods.
i. Accuracy
ii. Precision
Answer:
a) Precision
b) Accuracy
c) Accuracy and precision
d) Accuracy
Explanation:
When an experiment is done more than once to determine if the results are statistically ok, two forms of the validations are possible the accuracy and precision. When the values of the various experiments are close to the known value, then they are accurate. When the values are close to each other they are precise. So, sometimes the results are precise but are not accurate, and vice-versa.
a) Here, the person wants to find if the 5 aliquots will have close results, so, he or she is looking for precision.
b) Here the amount of analyte is already known, and the person wants to identify if the value will be the same when analyzed together with another sample, thus he or she is looking for accuracy.
c) Here the three results will be compared with each other (precision) and with the standard value of the method (accuracy).
d) The methods will be tested, and the values will be compared with the standard known value, so the person is looking for accuracy.
B. ethyl alcohol
C.sulfuric acid
D.All chemicals are potentially dangerous
Answer:
D.All chemicals are potentially dangerous
Explanation:
No chemical is toxicologically neutral
Answer:
nitrogen 18
nitrogen has an atomic number of 7
Answer : The number of drops pf the stock solution mist be added are, 50 drops.
Explanation :
As we are given that the concentration of stock solution 1 mg/mL and pipette delivers 20 drops/mL. That means,
1 mg of epinephrine = 1 mL = 20 drops
The final volume of Locke's solution = 25 mL
and the final concentration needed =
As, 1 mL of solution contains =
So, 25 mL of solution contains =
Conversion used :
Now we have to determine the number of drops needed.
As, 1 mg of epinephrine contains 20 drops.
So, 2.5 mg of epinephrine contains 2.5 × 20 = 50 drops.
Therefore, the number of drops pf the stock solution mist be added are, 50 drops.
If you want to achieve a final concentration of 100 µg/mL of epinephrine in a 25 mL solution, when using a stock solution of 1 mg/mL and a pipette that delivers 20 drops/mL, you need to add 50 drops of your stock solution.
Since we are asked to find the number of drops of stock solution required to achieve a final concentration of 100 µg/mL in a 25 mL solution, the first step is to convert the concentration of the stock solution to the same units, µg/mL. Hence, 1 mg/mL is equal to 1000 µg/mL. Further, we know that 1 mL of the stock solution contains 1000 µg of epinephrine, and our pipette delivers 20 drops/mL, so 1 drop of stock solution contains 1000 µg / 20 drops = 50 µg. Thus, if we need a 100 µg/mL concentration in 25 mL, we need a total of 100 µg/mL * 25 mL = 2500 µg of epinephrine. Therefore, to achieve this, we must add 2500 µg / 50 µg/drop = 50 drops of our stock solution. Hence,
50 drops
of the stock solution should be added to achieve the desired concentration.
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