In a calorimetry experiment, it was determined that a 92.0 gram piece of copper metal released 1860 J of heat to the surrounding water in the calorimeter (qcopper = −1860 J). If the final temperature of the copper metal-water mixture was 25.00°C, what was the initial temperature of the copper metal? The specific heat of copper is 0.377 J/(g°C). Group of answer choices Tinitial = 28.6°C Tinitial = −28.6°C Tinitial = 78.6°C Tinitial = 92.6°C Tinitial = 53.6°C

Answers

Answer 1
Answer:

Answer:

Tinitial = 78.6°C

Explanation:

In a calorimetry experiment, the flow heat is measured for a system that has a state change. In this case, there isn't happening a physical change, so the heat is called sensitive heat, and it's calculated by:

q = mxCpxΔT

Where q is the heat, m is the mass, Cp is the specific heat and ΔT is the difference of final and initial temperature (Tfinal - Tinitial).

Copper is losing heat, so q is negative, then:

-1860 = 92x0.377x(25 - Ti)

34.684(25 - Ti) = -1860

25 - Ti = -53.63

-Ti = -78.63

Ti = 78.6ºC


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Describe the environmental impacts that are involved during the design, research and development, and marketing phases of cell phones.

Answers

Answer:

joe mama

Explanation:

400 + 20 + 420

How many grams of Cl are in 31.2g CF2Cl2

Answers

Answer:

Mass = 42.6 g

Explanation:

Given data:

Mass of CF₂Cl₂ = 31.2 g

Mass of Cl₂ = ?

Solution:

Number of moles of CF₂Cl₂ = mass/molar mass

Number of moles =  31.2 g/121 gmol

Number of moles = 0.3  mol

1 mole of CF₂Cl₂ contain 2 moles of Cl atom.

0.3 mol × 2 = 0.6 mol

Mass of Cl:

Mass = number of moles × molar mass

Mass = 0.6 mol × 71 g/mol

Mass = 42.6 g

Which is the weakest type of intramolecular force/bond?a. Polar covalent b. Ionic c. Metallic d. Nonpolar covalent

Answers

Answer:

Non polar covlant

Explanation:

given that the only known ionic charges of lead are pb(ii) and pb(iv), how can you explain the existence of the pb2o3 salt

Answers

Answer:

See Explanation

Explanation:

Pb2O3 is better formulated as PbO.PbO2. It is actually a mixture of the two oxides of lead, lead II oxide and lead IV oxide.

This implies that this compound Pb2O3  (sometimes called lead sesquioxide) is a mixture of the oxides of lead in its two known oxidation states +II and +IV.

Hence Pb2O3  contains PbO and PbO2 units.

Consider a mixture of air and gasoline vapor in a cylinder with a piston. The original volume is 35 cm3. If the combustion of this mixture releases 775 J of energy, to what volume will the gases expand against a constant pressure of 710. torr if all the energy of combustion is converted into work to push back the piston

Answers

Answer:

The gases will expand 8.2 L against the constant pressure of 710 torr.

Explanation:

Given that:

the original volume V₁ = 35 cm³ = 35 × 10⁻⁶ m³

Since the combustion of the mixture releases energy then :

the work W = - 775 J

Pressure = 710 torr

Since 1 torr = 133.322 Pa

710 torr = 94658.62 Pa

We all know that:

W = -PdV

-775 = - 94658.62 Pa ( V₂ - V₁ )

-775 = - 94658.62 ( V₂ - 35 × 10⁻⁶)

-775/ - 94658.62 =  V₂ - 35 × 10⁻⁶

0.008187 = V₂ - 35 × 10⁻⁶

V₂ = 0.008187 + 35 × 10⁻⁶

V₂ = 0.008222 m³

The change in volume dV = V₂ - V₁

The change in volume dV = 0.008222 m³ - 35 × 10⁻⁶ m³

The change in volume dV = 0.008187   m³

To litres

The change in volume dV = 8.2 L

Thus, the gases will expand 8.2 L against the constant pressure of 710 torr.

How many oxygen molecules in 2.3x10-⁸g of molecular oxygen ​

Answers

Answer:

6.321 × 10^22

Explanation:

Mass of Oxygen =

3.36

g

Molar mass of oxygen (

O

2

) = 16 x 2 =

32

g

m

o

l

Total molecules in oxygen = Mass in grams/Molar mass x

N

A

=

3.36

32

x

6.02

x

10

23

=

6.321

x

10

22

Note:

N

A

(Avagadro's number) =

6.02

x

10

23

Hope it helps...