At a small zoo, 30% of the animals are reptiles. If there are 135 reptiles, how many total animals are at the zoo?

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Find the limit of the function by using direct substitution. limit as x approaches zero of quantity x squared plus eleven.
Circletowns limits forms perfect circular shape it has a population of 20,000 and a population density of 480 people per square kilometers

If there are 5 fish and 1 of the dies how many are left

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There are 4 living fish, but unless the dead one was taken from the tank, there are still 5 fish in the tank.

Given the following function , find f(-2) ,f (0) and f(2) F(X)=-3x-3 F(-2) = help me please i don't understand

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Answer:

$\large{f(-2)=3\n\nf(0)=-3\n\nf(2)=-9}$

Step-by-step explanation:

$f(x)=-3x-3\n\nf(-2)\to\text{put x = -2 to the equation of the function}\ f(x):\n\nf(-2)=-3(-2)-3=6-3=3\n-------------------------\nf(0)\to\text{put x = 0 to the equation of the function}\ f(x):\n\nf(0)=-3(0)-3=0-3=-3\n------------------------\nf(2)\to\text{put x = 2 to the equation of the function}\ f(x):\n\nf(2)=-3(2)-3=-6-3=-9$

After writing a $800 check to pay a bill, a student had a balance of $350 in his account. How muchdid he have in the account before he wrote the check?
a) Let X = his balance before writing the check. Write the equation you would use to solve this
problem.

Answers

The equation to solve the problem is X - $800 = $350. And the amount in his account before he wrote the check is $1150.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given that after writing an $800 check to pay a bill, a student had a balance of $350in his account.

We need to find out how much did he have in the account before he wrote the check.

The amount of the check = $800

The amount the student has in balance = $350

The amount the student had before he wrote the check.

Let X be the amount the student had before the check.

Now,

X - $800 = $350

X - 800 = 350 is our equation to find the amount the student has before the check.

The value of X can be written as,

We have,

X - $800 = $350

Add $800 on both sides

X = $350 + $800

X = $1150

Hence, the equation to solve the problem is X - $800 = $350. And the amount in his account before he wrote the check is $1150

Learn more about Equation here:

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Answer:

x=800+350

Step-by-step explanation:

The money spent plus the money he has left would equal the money he had in the first place.

Find a solution to the following initial-value problem: dy dx = y(y − 2)e x , y (0) = 1.

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This equation is separable, as

$(\mathrm dy)/(\mathrm dx)=y(y-2)e^x\implies(\mathrm dy)/(y(y-2))=e^x\,\mathrm dx$

Integrate both sides; on the left, expand the fraction as

$\frac1{y(y-2)}=\frac12\left(\frac1{y-2}-\frac1y\right)$

Then

$\displaystyle\int(\mathrm dy)/(y(y-2))=\int e^x\,\mathrm dx\implies\frac12(\ln|y-2|-\ln|y|)=e^x+C$

$\implies\frac12\ln\left|\frac{y-2}y\right|=e^x+C$

Since $y(0)=1$ , we get

$\frac12\ln\left|\frac{1-2}1\right|=e^0+C\implies C=-1$

so that the particular solution is

$\frac12\ln\left|\frac{y-2}y\right|=e^x-1\implies\boxed{y=\frac2{1-e^(2e^x-2)}}$

1 is 25% of what number?

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Answer:

25% of 4 is 1.

Step-by-step explanation:

100% of 4 is 4, therefore 25 percent of 4 equals 1.

Rewrite 3/11 amd 1/4 so they have a common denominator

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Hello!

Answer:

$\Large \boxed{\sf (12)/(44) ~~ and~~ (11)/(44) }$

Step-by-step explanation:

We want that the fractions 3/11 and 1/4 have a common denominator.

Let's find the LCM (least common multiple) of 4 and 11:

$\text{\sf Multiples of 4:}~~ \sf 4, 8, 12, 16, 20, 24, 28, 32, 36, 40, \boxed{\sf 44}, 48\n\n\text{\sf Multiples of 11:} ~~ \sf 11, 22, 33, \boxed{\sf 44}, 55, 66, 77, 88, 99, 110$

So the LCM of 4 and 11 is 44.

Convert fractions over 44:

$\sf (3)/(11) = (3 * 4 )/(11 * 4) = \boxed{\sf (12)/(44)}$

$\sf (1)/(4) = (1 * 11 )/(4 * 11) = \boxed{\sf (11)/(44)}$

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