A park is in the shape of a rectangle 8 miles long and 6 miles wide. How much shorter is your walk if you walk diagonally across the park than along two sides of it?
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Find the hypotenuse of the triangle.
a^2 + b^2 = c^2
Where 'a' and 'b' are the two legs and 'c' is the hypotenuse.
Plug in what we know:
6^2 + 8^2 = c^2
Simplify the exponents:
36 + 64 = c^2
Add:
100 = c^2
Find the square root of both sides:
c = 10
14 - 10 = 4
So walking diagonally across will be 4 miles shorter than walking around the edges.
this would be a right triangle with the legs being 8 miles and 6 miles. using the Pythagorean theorem, the hypotenuse would be 10 miles long. therefore, he would be walking a total of four miles less if he walked diagonally.
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WILL MARK BRAINLIEST!!!!!!! REALLY NEED HELP! The graph of the following compound inequality shows all the numbers between 4 and 8 including 4 but not including 8.True or false? 4 ≤ x < 8
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(-2/3)w + 8/27 = -4/5
(-2/3)w = -4/5 -8/27
-4/5 - 8/27 ⇒ (-4/5)(27/27) - (8/27)(5/5) ⇒ -108/135 - 40/135 = (-108-40)/135
= -148/135
(-2/3)w = -148/135
w = -148/135 ÷ -2/3
w = -148/135 * -3/2 = (-148*-3)/(135*2) = 444/270
w = 1 174/270 or 1 29/45
174 ÷ 2 = 87 ÷ 3 = 29
270 ÷ 2 = 135 ÷ 3 = 45
to check: w = 1 29/45 ⇒ ((1*45)+29)/45 = 74/45
(w-4/9)(-2/3) = -4/5
(74/45 - 4/9)(-2/3) = -4/5
(74/45 - (4/9 * 5/5))(-2/3) = -4/5
(74/45 - 20/45)(-2/3) = -4/5
((74-20)/45)(-2/3) = -4/5
(54/45)(-2/3) = -4/5
(54*-2)/(45*3) = -4/5
-108/135 = -4/5
-4/5 = -4/5
-108 ÷ 27 = -4
135 ÷ 27 = 5
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Hope I helped!
Answers
see explanations
Step-by-step explanation:
Formula for mid-point is;
1.Given S(-3,4), U(-3,0) and T(5,0) then finding the mid-points
SU = [(-3+-3)/2,(4+0)/2] =(-3,2)
TU= [(-3+5)/2,(0+0)/2] =(1,0)
ST=[(-3+5)/2,(4+0)/2]=(1,2)
2.Mid-point formula for this case given W(-5,1) and Z(3,3) will be;
Midpoint = [ (x₁+x₂)/2,(y₁+y₂)/2]
Midpoint= [(-5+3)/2 ,(1+3)/2]
Midpoint=(1,2)
3. Finding the length of segments and the midpoint of the segments
Formula for length of segment, d, is given as;
For C(-1,5) and D(5,1)
Midpoint of the segment CD will be
[(-1+5)/2,(5+1)/2] = (2,3)
For E (-3,-6) and F(5,0)
The midpoint for segment EF will be;
[(-3+5)/2 ,(-6+0)/2] =(1,-3)
For L(-4,4) and M(-1,-5)
Learn More
Midpoint of a segment :brainly.com/question/10424143
Distance of a segment :brainly.com/question/11591660
Keywords :midpoint, midpoint formula, segment length, line segment
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For this case we have that the main function is given by:
We apply the following transformation:
Vertical displacements:
Assume k> 0
To graph y = f (x) - k, move the graph k units down.
For k = 3 we have:
Answer:
when the function is changed to f (x) - 3 the change that will occur is:
Vertical displacement 3 units down.