The value of angle B is 121degree and Angle C is 59 degree, and Angle D has the same measure as the angle B
It is defined as the four-sided polygon in geometry having four edges and four corners and twopairs of congruent sides. It has one pair of opposite congruent angles.
We have a quadrilateral in which angle B and angle D are given.
As we know the opposite angles in the quadrilateral are same in measure.
10x - 19 = 7x + 23
3x = 42
x = 14
Angle B = 10x - 19 = 10(14) - 19 = 121 degree
Angle C = 7x + 23 = 7(14) + 23 = 121 degree
Angle A + Angle C = 360 - 121 -121 = 118
Angle C = 118/2 = 59
Thus, the value of angle B is 121degree and Angle C is 59 degree, and Angle D has the same measure as the angle B
Learn more about the quadrilateral here:
#SPJ2
Answer:
Measure B= 121
Measure C=59
Step-by-step explanation:
10x-19=7x+23
3x=42
x=14
plug in x to the problem and you'll find Measure B is 121 so to find Measure C you'll have to subtract 180 and 121 to get 59.
20 m
18.8 m
What is the area
Answer:
5715.2 cubic metres
Step-by-step explanation:
I'm assuming that by area you mean volume. If you just take 15.2 x 20 x 18.8 you find the volume, 5715.2 cubic metres.
Answer: 15.2 x 20 x 18.8 = 57, 152 m
Step-by-step explanation: Just multiply all numbers
Let's check the distributive property first :
where , , and are real numbers.
Now, to express 4x24 in the form , we just need to express 24 as a sum or subtraction.
Notice that we can express a 24 as a sum or subtraction in a number of ways:
1. 24-12=12, so 12+12=24
2. 24-10=14, so 10+14=24
3. 28-4=24, so 28-4=24
And so on...
Now let's use the distributive property:
1.
Since 24=12+12, we can express the same multiplication using the distributive property as:
2.
Since 24=10+14, we can express the same multiplication using the distributive property as:
3.
Since 24=28-4, we can express the same multiplication using the distributive property as:
As you can see, there are many ways to use the distributive property.
I believe the answer is:
Alexia arrives 1 hour later than Hailey.
Good luck! XD
Is there more to this question? The only math question I can think of that would go with this is for us to tell what a half dozen is equal to. If that is the case, the answer is 6.
OL
⊥
ON
start overline, O, L, end overline, \perp, start overline, O, N, end overline
\qquad m \angle LOM = 3x - 15^\circm∠LOM=3x−15
∘
m, angle, L, O, M, equals, 3, x, minus, 15, degrees
\qquad m \angle MON = 5x - 23^\circm∠MON=5x−23
∘
m, angle, M, O, N, equals, 5, x, minus, 23, degrees
Find m\angle MONm∠MONm, angle, M, O, N:
Segments LO and ON are perpendicular, providing the required
information for the value of the sum of ∠LOM and ∠MON.
Reasons:
The given parameter are;
is perpendicular to ;
m∠LOM = (3·x - 15°)
m∠MON = (5·x - 23°)
Required:
Find m∠MOM
Solution:
Given that is perpendicular to , we have;
m∠LON = 90° by definition of perpendicular lines
m∠LON = m∠LOM + m∠MON by angle addition postulate
Therefore;
m∠LOM + m∠MON = 90° by substitution property of equality
Which gives;
(3·x - 15°) + (5·x - 23°) = 90° by substitution property
8·x - 38° = 90°
x = 16°
m∠MON = 5·x - 23°
m∠MON = 5 × 16° - 23° = 57°
Learn more here:
Answer:57
Step-by-step explanation:
Answer:
Darin drove '2m - 20' miles.
Step-by-step explanation:
We are given that Sam drove 'm' no. of miles.
As, it is also given that Kara drove twice as many miles as Sam. Therefore we get that Kara drove '2m' no. of miles.
Now, it is given that Darin drove 20 miles fewer than Kara .i.e. Darin drove '2m - 20' no. of miles.
Hence, in terms of m, Darin drove '2m - 20' miles.