Answer:
27.5 m
Explanation:
Given:
u = 18 km/h = 5 m/s
v = 21.6 km/h = 6 m/s
a = 0.20 m/s²
Find: s
v² = u² + 2as
(6 m/s)² = (5 m/s)² + 2 (0.20 m/s²) s
s = 27.5 m
Answer:
Boiling is the "rapid vaporization of liquid" when the liquid is heated at the point where the pressure of the vapor is equal to the pressure exerted by the atmosphere in the liquid.
So during the boiling, the vaporization of the water is also occurring but is a little bit more complex.
Some questions that you may ask your friend to differentiate those two phenomena are:
Which one is used to cook things like pasta? (boiling)
in which process, a liquid is transformed into a gas? (evaporation)
Which one includes the other? (boiling)
Evaporation and boiling are both phases changes, but they differ in the specifics of how and when they happen. These differences involve the temperature and location within the liquid where they occur, as well as the speed of the process.
To differentiate between evaporation and boiling, you could ask your friend these questions:
By asking these questions, your friend will be able to identify the key differences that separate evaporation from boiling.
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As the particle moves along a straight line, the magnitude of the velocity is equal to the speed and the direction is along the direction of motion.
To find out the speed of the particle, we have to differentiate the given equation of motion. That is,
Speed =
For t=6 s, we get
Speed = 60₋ 9 × 6 = 60₋54=6 m/s
The speed of the particle at t=6 s is 6 m/s.
it just stop moving? If not, where does
it go?
Express the density numerically in grams per cubic centimeter.
B) None of the remaining light bulbs will be on.
C) Only the bulb closest to the switch will be on.
D) All three remaining light bulbs will be brighter than before.
The correct answer is option B) None of the remaining light bulbs will be on.
In a series connection when a bulb is removed, it will be creating a open circuit. Since the circuit is series and is open at a point current will not flow and hence the other bulb will not glow.
That's because the basic requirement for the circuit to operate a continuous, closed-loop path is no longer met. This is the main disadvantage of a series circuit. If any one of the light bulbs or loads burns out or is removed, the entire circuit stops operating.
Learn more about the series circuit here: brainly.com/question/19865219
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