Surrounding every moving electron isa. an electric field
b. a magnetic field
c. both a and b
d. none of the above
Answers
The correct statement is:
C. both a and b
What is electromagnetic radiation ?
Every moving electron has an electric field and a magnetic field around it. This is a fundamental tenet of electromagnetic radiation, often known as electromagnetism.
An electron produces both an electric field and a magnetic field while it is moving or accelerating. The electromagnetic waves created by the interaction of these fields and their spread out from the electron.
While the magnetic field interacts with moving charges and magnetic materials, the electric field is in charge of applying electric forces to other charged particles. Together, these fields are fundamental to many phenomena, such as electromagnetic wave transmission, the behavior of charged particles in electric and magnetic fields, and the operation of equipment like motors, generators, and antennas.
So, the correct Option is that both an electric field and a magnetic field surround every moving electron.
Therefore, (Option C) is correct
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Answers
Answer:
207°
Explanation:
You start at the positive x axis and move counter clockwise. So half a circle is 180° + 27° = 207°
Answers
Final Answer:
To determine if the strength of the electric field decreases as 1 over distance squared (1/r²), we need to measure the electric field at 0.5 m and 1 m directly above the midpoint of a small dipole created by two charges brought very close together.
Explanation:
In this experiment, you're examining the electric field generated by a small dipole. The electric field strength at a distance from a dipole does follow an inverse square law, as suggested by 1/r², which is a fundamental principle of electrostatics. This means that the electric field's strength decreases as you move farther away from the charges.
To verify this, you'll measure the electric field at two different distances (0.5 m and 1 m) directly above the midpoint of the dipole. By comparing these measurements, you can assess whether the field strength obeys the 1/r² relationship. The electric field strength should be four times stronger at 0.5 m than at 1 m if it follows the 1/r² law.
This experiment provides hands-on insight into the behavior of electric fields and their relationship to distance, supporting the foundational principles of electrostatics.
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motion and light
electricity and motion
electricity and magnetism
Answers
In short, Option D) Electricity and Magnetism would be your answer.
Hope this helps!
Answers
If you are bombarded with 1.00 mol of photons with a wavelength of 370 nm, you are being subjected to 322 kJ/mol of energy.
The energy of a photon is given by the equation:
E = hc/λ
where:
h = Planck's constant = 6.626 x J s
c = speed of light = 2.998 x m/s
λ = wavelength of the radiation
To find the energy of a mole of photons, we need to multiply the energy of a single photon by Avogadro's number (6.022 x ).
First, we need to convert the wavelength of the radiation from nanometers to meters:
370 nm = 370 x m
Now, we can use the equation to calculate the energy of a single photon:
E = hc/λ
E = (6.626 x J s) x (2.998 x
m/s) / (370 x
m)
E = 5.35 x J
Next, we can calculate the energy of a mole of photons:
(5.35 x J/photon) x (6.022 x
photons/mol) = 3.22 x
J/mol
Finally, we can convert the energy to kilojoules per mole of photons:
3.22 x J/mol = 322 kJ/mol
To know more about wavelength refer here
brainly.com/question/31143857#
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Answers
The weight of the passenger plusethe speed of travel prior to the collision will be multiplied togetherto equal the force their body will endure.
For ex. the force aperson will be subjected to for a passenger weighing 100 pounds, in avehicle traveling at 60 mph, will be the equivalent of 6000 pounds hitting a brick wall.
I hope this helps:)
Answers
Answer;
B. Effective length of the tube.
Explanation;
- Most wind instruments are of either the open-open tube or the open closed tube type. Open ends of the tubes makes contact with the outside, atmospheric air.
- At an open end, when the air is disturbed in the wind instruments, the air vibrates with a variety of frequencies, however the frequencies that correspond to the natural frequencies will persist.
- Effective Length of the tube is responsible for determining the frequency of vibration of the air column in the pool with in a wind instrument.
The effective length of the tube is responsible for determining the frequency of vibration of the air column in the tube within a wind instrument.