Ruff, the 50 cm tall Labrador Retriever stands 3 m from a plane mirror and looks at his image. What is Ruff’s image position and height?

Answers

Answer 1
Answer: Since the mirror is plane, the image will be formed behind the mirror. The distance will be the same as that of the distance of the object from the mirror and the height will just be the same.
So, Ruff's image will be 3 m behind the mirror and 50 cm tall.

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Walking across a carpet is an example of charge being transferred bya. contact.
b. induction.
c. static electricity.
d. friction.

Answers

Answer : The correct answer is- D)  Friction.

There are three modes of charging, which are Conduction, induction, and friction.

The static electricity is produced due to the rubbing of one substance with another. This is called charing by friction.


Hence, the correct answer is friction as there is friction between carpet and the feet of person walking over it.

Walking across a carpet is an example of charge being transferred by friction. The answer is letter D. The carpet, which is at rest, will resist the motion cause by your walking. This resistive motion d the friction the carpet obtained from you and you from the carpet.

Remote controls enable users to adjust the volume and channel of televisions without having to touch the television. Which of these best describes the signals sent by remote controls to televisions?

Answers

Answer:

When you use your control remote, you can see that there is not a "material" thing that comes out of the control remote and goes to the TV, but there is actually energy that comes from the control remote (and this is why your control remote needs battery)

This energy is called an "electromagnetic wave" usually in the infrared range, this means that the energy that comes from the control remote has less energy than the visible red light (and this is why we can not see the light that comes out of the control remote), and this "signal" is read by the TV, in order to change of channel or change the volume.

You even can see that there is a sort of light (electromagnetic wave) coming out from it if you point with a camera to the small bulb that is in the front of the control remote.

Answer:electromagnetic wave

Explanation:

When you anticipate the results of your experiment before you begin, you are making a

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Hi There!

When you anticipate the results of your experiment before you begin, you are making a prediction?

So the answer is 
prediction

What are semi- conductors?

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a solid substance that has a conductivity between that of an insulator and that of most metals, either due to the addition of an impurity or because of temperature effects. answer from google

Heat transfer occurs

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It depends on the tempature of something or an object,
 The Object has to go from hot to cold, that is a primary example of how heat transfer occurs

A golfer is on the edge of a 12.5 m bluff overlooking the 18th hole which is located 60 m from the base of the bluff. She launches a horizontal shot that lands in the hole on the fly. The gallery erupts in cheers.

Answers

Answer:

The ball impact velocity i.e(velocity right before landing) is 6.359 m/s

Explanation:

This problem is related to parabolic motion and can be solved by the following equations:

x=V_(o)cos \theta t----------------------(1)

y=y_(o)+V_(o) sin \theta t - (1)/(2)gt^(2)---------(2)

V=V_(o)-gt ----------------------- (3)

Where:

x = m is the horizontal distance travelled by the golf ball

V_(o) is the golf ball's initial velocity

\theta=0\° is the angle (it was  a horizontal shot)

t is the time

y is the final height of the ball

y_(o) is the initial height of the ball

g is the acceleration due gravity

V is the final velocity of the ball

Step 1: finding t

Let use the equation(2)

t=\sqrt{(2 y_(o))/(g)}

t=\sqrt{(2 (12.5 m))/(9.8 m/s^(2))}

t=1.597s

Substituting (6) in (1):

67.1 =V_(o) cos(0\°) 1.597-------------------(4)

Step 2:  Finding V_(o):

From equation(4)

67.1 =V_(o)(1) 1.597

V_0 = (6.71)/(1.597)

V_(o)=42.01 m/s (8)  

Substituting V_(o) in (3):

V=42.01 -(9.8)(1.597)

v =42 .01 - 15.3566  

V=26.359 m/s