For graphs, always start with line x then do line y.
The real-world problem that could be modeled by a linear function will be y = 60 - 12x.
A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.
The linear equation is given as,
x/a + y/b = 1
Where 'a' is the x-intercept of the line and ‘b’ is the y-intercept of the line.
The linear function whose x-intercept is 5 and y-intercept is 60. Then the equation is given as,
x/5 + y/60 = 1
Convert the equation into a slope-intercept form. Then we have
x/5 + y/60 = 1
12x + y = 60
y = 60 - 12x
The real-world problem that could be modeled by a linear function will be y = 60 - 12x.
More about the linear equation link is given below.
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Answer:
Based on the data provided, Sergei can make the following predictions and set a benchmark for his performance:
Prediction 1: With consistent training and improvement over the summer, Sergei can predict that he will run the mile faster than 8:45 in his upcoming tryouts. This is based on the pattern of improvement he has shown from 9:30 (eighth grade) to 8:45 (freshman year) and his continued training.
Prediction 2: Sergei can aim to break the 8-minute mark for the mile based on the trend of his improvements. This is a reasonable goal given his past progress, and it aligns with his objective of making the varsity team where all runners need to run under 6:15.
Benchmark: The benchmark against which Sergei is measuring his performance is the time required to run a mile. He's tracking his progress in terms of how long it takes him to complete a mile, aiming to continuously improve and meet the varsity team's standard of running under 6:15 for the mile.