She left her home in Kansas City at 5am. She arrived at the beach at 6pm. How long did it take Ms. W to travel to her destination?
Answers
Answer:To determine how long it took Ms. W to travel to her destination, we need to calculate the time difference between her departure and arrival times.
1) Departure time:
Ms. W left her home in Kansas City at 5am.
2) Arrival time:
Ms. W arrived at the beach at 6pm.
3) Time difference:
To calculate the time it took for Ms. W to travel, we need to find the difference between the departure and arrival times.
The time difference between 5am and 6pm is 13 hours. This includes the 12 hours from 5am to 5pm, and an additional hour from 5pm to 6pm.
Therefore, it took Ms. W 13 hours to travel from her home in Kansas City to the beach.
Step-by-step explanation:
Hope This Helps
Answer:
Step-by-step explanation:
13 hours
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Explain how to determine the maximum and minimum values of a function by examining its graph.
Answers
Answer:
he forgot to solve the -6 i hope thats right im srry if it isnt
Step-by-step explanation:
Answer:
-1=x
Step-by-step explanation:
They messed up on step 4. instead of -2x it should be -10x. When they switched -6 over to the opposite side they forgot to use the opposite symbol. They did 6-4 instead of 4+6.
Answers
1ft³=0.5 tons
Cross multiply
1x=13.5tons
x=13.5tons
So one scoop/load carries 13.5 tons of sand. Lets see how many 120 loads can carry.
13.5tons*120loads=1620 tons of sand
Now lets see how freight cars it would take to hold 1620 tons of sand
1620/40=40.5 freight cars
Since you can't have .5 of a freight car, lets round 40.5 up to 41
Answer=41 freight cars
Answer:
40.5
Step-by-step explanation:
Answers
120*4=480
480/3=160
160/10=16
16*4=64
Hope you understand it
a - { a - [ a- (2a - b) + 3a ]}
Answers
= a - {a - (a - 2a + b + 3a)}
= a - {a - (2a + b)}
= a - (a - 2a -b )
= a - (-a - b)
= a + a + b
= 2a + b
3,659 in ^3
11,488 in ^3
2,964 in ^3
944 in ^3
Answers
a) A balloon has a circumference of 28 in. Use the circumference to approximate the volume of the balloon to the nearest cubic inch.
or
b) A balloon has a circumference of 28 in. Use the circumference to approximate the surface area of the balloon to the nearest square inch.
case a)
we know that
circumference=2*pi*r
clear variable r
r=circumference/(2*pi)
circumference=28 in
r=28/(2*pi)----> r=4.46 in
volume of a balloon=(4/3)*pi*r³-----> (4/3)*pi*4.46³----> 371.61 in³
Volume=372 in³
the answer is
372 in³
case b)
we know that
circumference=2*pi*r
clear variable r
r=circumference/(2*pi)
circumference=28 in
r=28/(2*pi)----> r=4.46 in
surface area of a balloon=4*pi*r²-----> 4*pi*4.46²---> 249.83 in²
Surface area=249.83 in²-------> 250 in²
the answer is
250 in²
A = sq. in.
Answers
Answer
Area of a regular hexagon is given by:
.....[1]
where,
A is the area of a regular hexagon
a is the side of the hexagon.
As per the statement:
Perimeter of a regular hexagon is 48 inch.
Perimeter(P) of a regular hexagon is given by:
Substitute the given values we have;
Divide both sides by 6 we have;
or
a = 8 inch.
Substitute the value of a = 8 inches in [1] we have;
⇒
Therefore, the area of a regular hexagon is sq. in