Solve the following equation
w-6/5=-2
Answers
First, move
Second, subtract the numerator (6) and -2.
Answer as fraction:
Answer as decimal: -0.8
Related Questions
Claire and her partner, Grace, are throwing for the javelin event as a team. Claire threw the javelin 42 5/8 feet and Grace threw it 39 3/5 feet. How far did the team throw the javelin? Show your work.
A spinner and 2 cards are shown below:A spinner with 7 equal sectors is shown in the figure. The colors Green, Red, Orange, Violet, Pink, Yellow, and Blue are marked on it. The arrow points at the red color. Two cards are shown on the right side. The colors Purple and Green are marked on them. Sophie spins the spinner and picks up a card without looking. What is the probability that the spinner stops at red and a green card is selected? 1 over 49 1 over 16 1 over 14 1 over 2
Bethany is paid $617.09 biweekly. What is her average monthly net income?$873.26 $1,337.03 $617.09 $1,500.00
A circular skating rink has a radius of 40 feet. Which expression can be used to find the circumference of the skating rink, in feet?
Answers
Answer:50
explanation: 2500 divided by 50 is 50
P(two boys and one girl)
P(at least two girls)
I don't care if you cab only answer one, I would very much appreciate it if you still answered that one instead of nothing.
Answers
Answer:
1)
2)
3)
Step-by-step explanation:
Given : Mr. and Mrs. Romero are expecting triplets. Suppose the chance of each child being a boy is 50% and of being a girl is 50%.
To Find : The probability of each event.
1) P(at least one boy and one girl)
2) P(two boys and one girl)
3) P(at least two girls)
Solution :
Let's represent a boy with B and a girl with G
Mr. and Mrs. Romero are expecting triplets.
The possibility of having triplet is
BBB, BBG, BGB, BGG, GBB, GBG, GGB, GGG
Total outcome = 8
1) P(at least one boy and one girl)
Favorable outcome = BBG, BGB, BGG, GBB, GBG, GGB=6
2) P(at least one boy and one girl)
Favorable outcome = BBG, BGB, GBB=3
3) P(at least two girls)
Favorable outcome = BGG, GBG, GGB, GGG=4
Let's represent a boy with B and a girl with G
For example BBB is three boys and BGB is two boys and one girl.
These are all the possibilities
1) BBB
2) BBG
3) BGB
4) BGG
5) GBB
6) GBG
7) GGB
8) GGG
There is in total 8 different possibilities.
Now let's analyze the conditions
p (at least one boy and one girl)
That excludes only BBB and GGG so they are 6 possibilities out of 8
p = 6/8 = 3/4
p (two boys and one girl).
Those are 3 out of 8
p = 3/8
p (at least two girls)
Those are 3 (two girls) + 1(three girls) = 4
P = 4/8 = 1/2
Please, let me know if this was satisfactory for you.
Answers
Amount paid = $0.85(p - 5)
If the discount is applied first.
Amount paid = $0.85p - 5
Amount paid more if the coupon is applied first is 0.85(p - 5) - (0.85p - 5) = 0.85p - 4.25 - 0.85p + 5 = 0.75
Therefore, you will pay $0.75 more if the coupon is applied first rather than the 15% discount first.
Answer:
3; all real numbers except x=2
0.75
Answers
using the expression 14.99(n) + 4.99, the total of 3 CDs would cost $49.96.
- 7x + y = 4
8x - 3y = 1
X=
y =
Answers
Answer:
x=-1 y=-3
............
Answer:
(−1,−3) or x=−1,y=−3
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Answers
Answer:
Profit = $18.8 per meal
Step-by-step explanation:
Chef ordered beef = 4 pounds
Cost of beef = $3.25 per pound
Total cost of beef = 4 × 3.25 = $13
Amount of potatoes ordered = 6 pounds
Cost of potatoes = $1.96 per pound
Total cost of potatoes = 6 × 1.96
= $11.76
Amount of carrots ordered = 5 pounds
Cost of carrots = $1.81 per pound
Total cost of carrots = 5 × 1.81 = $9.05
Total amount of beef, potatoes and carrots = $13 + $11.76 + $9.05
= $33.81
Number of meals prepared with material purchased = 28
Per meal cost = = $1.2075
Selling price of one meal = $20
Profit per meal = Selling price - Cost price
= 20 - 1.2075
= 18.7925
≈ $18.8
Therefore, he will make $18.8 for each meal.