Explain how to determine the maximum and minimum values of a function by examining its graph.
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when you see the sign not facing the"y" the lin is the maximum value
whenever you see the sign not facing the "y" the line will be maximum value
i hoped i help :)
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Which letter has rotational symmetry?
Darlene purchases 20,000 worth of stock on her brokers advice and pays her broker a 1.5% broker fee darlene purchases 20,000 worth of stock on your brokers advice and pays her broker a 1.5% broker freeshe sells her stock when it increases to $28,600.02 years later and uses a discount broker who charges $21 per trade compute Darlenes net proceeds after the broker fees are taken out
Need help ASAP! Anyone know?
What numbers add to 8 and multiply to 11
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4x + 20 = x + 5(x+4) - 2x
expand the right hand side :
4x + 20 = x + 5x + 20 -2x
Collect up all the x terms on the right hand side: 4x + 20 = x + 5x - 2x + 20
So the total number of "x" 's on the right hand side is 1 + 5 -2 = 4
4x + 20 = 4x + 20
Hey ! look at that ! you've got the same thing on both sides of the equation ! this means that it doesn't matter what value x is, the equation works for ALL values of x . ( ANSWER)
Picture on bottom
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Working;
AM=AD+DM
=x+5+2x-1
=(3x+4) units
why does y=mx+b ?
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Answer:
The coordinates of every point on the line will solve the equation if you substitute them in the equation for x and y. The equation of any straight line, called a linear equation, can be written as: y = mx + b, where m is the slope of the line and b is the y-intercept
Step-by-step explanation:
lol thx for the points
Answers
Answers
2^14=10,000
d=3n
d=3(14)
d=42
d=days
n=number of times of reproduction
Final answer:
It would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.
Explanation:
To find out how long it would take for a single-cell amoeba to produce a population of about 10,000 amoebae, we need to calculate the number of times the amoeba doubles. Since the amoeba doubles every 3 days, we can find out the number of doubling periods it would take to reach 10,000 amoebae by dividing 10,000 by 2. This equals approximately 9.965, which means the amoeba would need to double about 9.965 times. Since we can't have a fraction of a doubling period, we can round it up to 10.
Each doubling period is 3 days, so to find out how long it would take, we can multiply the number of doubling periods (10) by the time interval for each doubling period (3 days). 10 x 3 = 30. Therefore, it would take approximately 30 days for a single-cell amoeba to produce a population of about 10,000 amoebae.
Learn more about Exponential Growth
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2. a(n)=10(2)n-1
3. a(n)=10+2n
4. a(n)=10+2(n-1)