A circus performer is shot out of a cannon at a 50° angle. He reaches a height of 25m. What was the initial velocity?a. How long will he fly before he hits the safety net set at ground level with a hole underneath it. (The circus wanted it to look like he was going to hit the ground and then he bounces, for the thrill effect)
Answers
Answer:
28.9 m/s
4.52 s
Explanation:
Given in the y direction:
s = 25 m
u = U sin 50°
v = 0 m/s
a = -9.8 m/s²
Find: U
v² = u² + 2as
0² = (U sin 50°)² + 2 (-9.8) (25)
U = 28.9 m/s
Given in the y direction:
s = 0 m
u = 28.9 sin 50° = 22.1 m/s
a = -9.8 m/s²
Find: t
s = ut + ½ at²
0 = (22.1) t + ½ (-9.8) t²
t = 4.52 s
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A car that travels from point A to point B in four hours, and then from point B back to point A in six hours. The road between point A and point B is perfectly straight, and the distance between the two points is 240 km. What is the car’s average velocity?
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Answer:
0.00034 m
Explanation:
Since the length of the aluminium bar, L is given by , L = 1.0000 + 2.4 × 10⁻⁵T and T = 14.1°C, we substitute the value of T into L. So, we have L = 1.0000 + 2.4 × 10⁻⁵ × 14.1°C = 1.0000 + 0.0003384 = 1.0003384 m. The change in length is thus 1.0003384 - 1.0000 = 0.0003384 m ≅ 0.00034 m
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B. It extended the provisions of the Pregnancy Discrimination Act.
C. It extended the provisions of Title VII to previously exempt
employers.
OD. It prohibited different wages for men and women performing the
same work.
Answers
The main effect of the Equal Employment Opportunity Act of 1972 was option C: It extended the provisions of Title VII to previously exempt employers. This act expanded the coverage of Title VII of the Civil Rights Act of 1964 to include state and local governments, public educational institutions, and some private and public employment agencies. It aimed to address and prohibit employment discrimination based on race, color, religion, sex, or national origin by a wider range of employers and entities.
Final answer:
The main effect of the Equal Employment Opportunity Act of 1972 was C. It extended the provisions of Title VII to previously exempt
employers.
Explanation:
The main effect of the Equal Employment Opportunity Act of 1972 (EEOA) was to extend the coverage of Title VII of the Civil Rights Act of 1964 to previously exempt employers. Before the EEOA, Title VII applied only to employers with 25 or more employees, leaving smaller employers unaffected. The EEOA expanded the reach of Title VII to include employers with 15 or more employees.
This significant change aimed to combat employment discrimination on the basis of race, color, religion, gender, or national origin more comprehensively by ensuring that a broader range of employers adhered to anti-discrimination measures.
Learn more about Equal Employment Opportunity Act of 1972 here:
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B. The magnet attracts paper, which pulls the ball. C. The paper exerts a force on the ball, Which pulls the ball towards the magnet.
D. The size of the ball attracts to the ball towards the magnet.
Answers
A steel ball, a magnet, and a piece of paper are used in an activity by a pupil. The ball is under the influence of the magnet. Therefore, choice A is right.
What is a magnet?
When electric charges move, a phenomenon known as magnetism is produced. These tiny movements can occasionally be found inside a material known as magnets. Magnets and the magnetic fields created by moving electric charges can attract or repel other magnets, which can also change how other charged particles move.
Because they can support a magnetic field that lasts forever, some materials, like iron, are categorized as permanent magnets. These are the magnets that are typically encountered in day-to-day life. Other materials like iron, cobalt, and nickel can be briefly given a magnetic field when placed inside a stronger, bigger magnetic field, but they will eventually lose their magnetic qualities.
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Answer:b
Explanation:
Answers
Answer:
as we find the resultant of the magnetic field we get in the xy plane. Just perpendicular to this plane i.e. along z-axis the charge is moving. Hence the force acting on the charge will also be in the xy plane.
Net field = ./(0.078^2 +0.070^2) = 0.105 T
Angle with x axis is arc tan 0.070/0.072 = 44.2 deg
So the force acting on the moving charge is got by Bqv
0.105*5.5*10^-5 * 6*10^3 = 0.03465 N
So the angle inclined by this force with x axis will be 90+44.2 = 134.2
Explanation: