Cole had 62.6 grams of pepper. Then he used 0.49 grams of the pepper to make somescrambled eggs. How much pepper does Cole have left?

Answers

Answer 1
Answer:

Answer:

Cole has 62.11 grams of pepper left.


Related Questions

Eight over three times three over one
A keyboard that costs $475 is marked down 15% for sale what is the reduced price of the keyboard
The measure of the supplement of an angle is 30 less than four times the measure of the complement of the angle. find the measure of the angle.
Please help! I really need help I have more questions that I'll post after​
The area of triangle AED is 20 square meters. Find the area of parallelogram ABCD.20 square meters52 square meters15 square meters104 square metersdiagram below.

12x2 – 14x - 10
Factored form

Answers

Answer:

2(2x + 1)(3x - 5)

Step-by-step explanation:

What is the factored form of x^2 +8x+15

Answers

Answer:

(x+3)(x+5)

Step-by-step explanation:

what two numbers will multiply to 15 and add up to 8?

3 and 5

so

(x+3)(x+5)

Find the first five terms of the sequence defined by each of these recurrencerelations and initial conditions.
a) an = 6an-1, a0 = 2
b) an = −2an-1, a0 = −1
c) an = an-1 – an-2, a0 = 2, a1 = −1

Answers

a) The first five terms of the sequence are 2, 12, 72, 432, 2592.
b) The first five terms of the sequence are -1, 2, -4, 8, -16.

c) The first five terms of the sequence are 2, -1, -3, -2, 1.

To find the first five terms of the sequence defined by each of these recurrence relations and initial conditions, we will use the given recurrence relation and initial conditions to find the next terms in the sequence.

a) an = 6an-1, a0 = 2

The first term is given as a0 = 2. We will use the recurrence relation to find the next terms.
a1 = 6a0 = 6(2) = 12
a2 = 6a1 = 6(12) = 72
a3 = 6a2 = 6(72) = 432
a4 = 6a3 = 6(432) = 2592

So, the first five terms of the sequence are 2, 12, 72, 432, 2592.

b) an = −2an-1, a0 = −1

The first term is given as a0 = -1. We will use the recurrence relation to find the next terms.
a1 = -2a0 = -2(-1) = 2
a2 = -2a1 = -2(2) = -4
a3 = -2a2 = -2(-4) = 8
a4 = -2a3 = -2(8) = -16

So, the first five terms of the sequence are -1, 2, -4, 8, -16.

c) an = an-1 – an-2, a0 = 2, a1 = −1

The first two terms are given as a0 = 2 and a1 = -1. We will use the recurrence relation to find the next terms.
a2 = a1 - a0 = -1 - 2 = -3
a3 = a2 - a1 = -3 - (-1) = -2
a4 = a3 - a2 = -2 - (-3) = 1

So, the first five terms of the sequence are 2, -1, -3, -2, 1.

Learn more about Recurrence

brainly.com/question/16931362

#SPJ11

Express 4 less than one-thirteenth of some number,w can be expressed algebraically as?

Answers

1/13w - 4 is how this can be expressed algebraically.
for some number w above equation can be expressed as follows:

(w)/(13) - 4

Please help me I need to get this done

Answers

The square root of 64 is 8 and the square root of 100 is 10.... so,

square root of 64/100 = 8/10

8/10 reduces to 4/5

Answer D.

The general term for the sequence 3/4, 6/5, 9/6, 12/7, 15/8 is?

Answers

Answer:

Sequence  (3n)/(3+n).

Step-by-step explanation:

Given : sequence 3/4, 6/5, 9/6, 12/7, 15/8 .

To find : The general term for the sequence.

Solution : We have given that 3/4, 6/5, 9/6, 12/7, 15/8 .

Here numerators are 3 , 6, 9 , 12, 15

Denominators are 4 ,5 , 6, 7, 8.

We can see in numerators all are multiple of 3

As,    3 × 1 , 3 × 2, 3 × 3 ...... etc

We can write it as  : 3n

Denominator are 3 +1 , 3 +2 , 3 +3 ..........etc

We can write it as 3 +n

So , sequence become (3n)/(3+n)

Therefore, sequence  (3n)/(3+n).

The numerators  = 3n ( where n = sequence number of the term
The denominators  = n + 3

Answer is  3n / (n + 3)