The rates of the forward and reverse reactions are unequal.
The concentrations of the products and reactants do not change.
The forward reaction stops at 500 K.
The correct option is this: THE CONCENTRATION OF THE PRODUCTS AND THE REACTANTS DO NOT CHANGE.
A reversible chemical reaction is said to be in equilibrium if the rate of forward reaction is equal to the rate of backward reaction. At this stage, the concentrations of the products and the reactants remain constant, that is, there is no net change in the concentration even though the reacting species are moving between the forward and the backward reaction.
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B. a nonmetal and a metal.
C. an acid and oxygen.
D. a base and an acid.
A salt is obtained as a reaction between a base and an acid which is option D.
A salt is obtained as a reaction between a base and an acid. In this reaction, the base donates a hydroxide ion (OH⁻) and the acid donates a hydrogen ion (H⁺). The hydroxide ion and hydrogen ion combine to form water (H₂O), and the remaining ions from the base and acid combine to form the salt. The salt is typically composed of a metal cation from the base and a non-metal anion from the acid. The formation of salt is a neutralization reaction where the acidic and basic properties of the reactants are neutralized, resulting in the formation of a new compound, the salt.
Hence, the correct option is option d.
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(2) 2.0 L of Kr (4) 1.5 L of Ar
Answer: (1) 1.0 L of Ne
Explanation: According to Avogadro's law, 1 mole of every gas occupy 22.4 Liters at STP and contains avogadro's number of particles.
Avogadro's Law: This law states that volume is directly proportional to the number of moles of the gas at constant pressure and temperature.
(At constant temperature and pressure)
Thus equal volumes contain equal number of atoms.
Hence, 1.0 liter of helium contains the same total number of atoms as
1.0 L of Ne at STP.
Answer:
B
Explanation:
H2 + O2 => H2O.
Then, balanced, as
2H2 + O2 = 2H2O
There we see that we need 2 times more mol of H2 than O2. So mol of O2 is 1/2 mol of H2. That is 27.4 mol / 2 = 13.7 mol.