Electrons are distributed around the nucleus and occupy almost all the volume of the atom.
The nucleus is made of electrons and protons.
The nucleus is made of protons, electrons, and neutrons.
The answer is (B) Electrons are distributed around the nucleus and occupy almost all the volume of the atom.
Carbon is a naturally occurring element that can be obtained from various sources, both organic and inorganic. It is separated from other substances by Filtration, Distillation, and Chemical Reactions.
Carbon is the fourth-most abundant element in the universe and is a key component of all known life forms. Here are some common methods for obtaining and separating carbon from other substances:
Organic Sources: Carbon is a fundamental element in organic compounds, which are compounds containing carbon atoms bonded to hydrogen and other elements. Organic sources of carbon include:
Fossil Fuels: Coal, oil, and natural gas are rich in carbon. Carbon can be obtained from these sources through processes like combustion, pyrolysis, or gasification.
Biomass: Plant and animal matter, such as wood, leaves, and agricultural residues, contain carbon. Carbon can be extracted from biomass through processes like carbonization or fermentation.
Inorganic Sources: Carbon can also be obtained from various inorganic sources:
Carbonates: Minerals like limestone (calcium carbonate) and dolomite contain carbon in the form of carbonate ions. Carbonates can be thermally decomposed to release carbon dioxide gas, which can then be captured and processed.
Graphite and Diamond: These are naturally occurring forms of carbon. Graphite can be obtained from certain rocks and is used in various industrial applications. Diamonds, although much rarer, are another crystalline form of carbon.
Separation from Other Substances:
Filtration: If carbon is present in a solid mixture, it can be separated using filtration. A porous material (filter paper or a sieve) is used to separate solid carbon particles from other substances based on particle size.
Distillation: If carbon is mixed with liquids that have different boiling points, distillation can be used. The mixture is heated, and the component with the lower boiling point (liquid) vaporizes first, while carbon remains in the original container.
Chemical Reactions: Carbon can be separated from other substances through chemical reactions. For example, carbonates can be treated with acid to produce carbon dioxide gas, leaving behind other components.
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Answer:
Carbon products are obtained by heating coal (to give coke), natural gas (to give blacks), or carbonaceous material of vegetable or animal origin, such as wood or bone (to give charcoal), at elevated temperatures in the presence of insufficient oxygen to allow combustion.
Explanation:
Orbitals are the regions where the possibility of finding the electrons are the most. -2, -1, 0, 1, 2, are the possible values of ml for an electron in a d orbital.
The ml will be 2 for the d -orbitals and is defined by the principal quantum number or the magneticquantum number. It states the orientation of the orbital and ranges from – l ≤ ml ≤ l.
As, ml for d orbitals = 2, then, -2, -1, 0, 1, 2 are the possible values that ranges from -l to +l.
Therefore, -2, -1, 0, 1, 2 are the values of ml.
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Answer : The percent yield of is, 68.4 %
Solution : Given,
Mass of = 0.16 g
Mass of = 0.84 g
Molar mass of = 16 g/mole
Molar mass of = 32 g/mole
Molar mass of = 44 g/mole
First we have to calculate the moles of and .
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 2 mole of react with 1 mole of
So, 0.026 moles of react with moles of
From this we conclude that, is an excess reagent because the given moles are greater than the required moles and is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of
From the reaction, we conclude that
As, 2 mole of react to give 1 mole of
So, 0.026 moles of react to give moles of
Now we have to calculate the mass of
Theoretical yield of = 0.572 g
Experimental yield of = 0.391 g
Now we have to calculate the percent yield of
Therefore, the percent yield of is, 68.4 %