Answer:
C3H6 + Br2 = C3H6Br2
The product formed is 1,2-dibromopropane.
The red-brown color of the bromine disappears, leaving a colorless liquid
Explanation:
C3H6 + Br2 = C3H6Br2
The product formed is 1,2-dibromopropane.
This is a direct addition reaction. The one molecule of bromine (Br2) joins the organic compound C3H6 to form one molecule of C3H6Br2.
This seemed unlikely at first, but one must look more closely at the C3H6. This is not a straight alkane (e.g., propane). Propane has the formula C3H8:
H3-C-C2-CH3
The molecule C3H6 is propylene (or propene). It has a double bond between two carbons.
H3-CH-CH=CH2
The compound in the question is propylene. When exposed to bromine, the carbon double bond breaks and a bromine atom is attached to each carbon:
H3-CH-CH=CH2 + Br2 = H3-CH-CHBr-CHBr
When propene reacts with bromine, the red-brown color of the bromine is lost and the product is a colorless liquid.
Question:
What is the balanced chemical equation for the reaction used to calculate ΔH∘f of BaCO3(s)?If fractional coefficients are required, enter them as a fraction (i.e. 1/3). Indicate the physical states using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) for aqueous solution.
EXPRESS ANSWER AS A CHEMICAL EQUATION. Please explain for me too!!!
Answer:
You will get at first carbon dioxide by burning C:
C+O_2=CO_2
Burn hydrogen to obtain water:
H_2+\frac{1}{2}O_2=H_2O
Combine them:
CO_2+H_2O=H_2CO_3
Now react it with Ba:
Ba+H_2CO_3=BaCO_3+H_2
To sum up, the reaction is Ba+C+\frac{3}{2}O_2=BaCO_3, using hydrogen as a catalyst.
Explanation:
Answer: Therefore, the molar mass of the unknown substance is 68.4 g/mol.
Explanation: We can use the freezing point depression equation to solve for the molar mass of the unknown substance:
ΔT = Kf × m
where ΔT is the change in freezing point, Kf is the freezing point depression constant of the solvent (naphthalene), and m is the molality of the solution.
First, we need to calculate the molality of the solution:
molality = moles of solute / mass of solvent (in kg)
We don't know the number of moles of the unknown substance, but we can assume that the naphthalene does not contribute significantly to the total mass of the solution (since its mass is much smaller than the mass of the unknown substance). Therefore, we can use the entire mass of the solution (1000g + 12.3g = 1012.3g) as the mass of solvent.
mass of solute = 1000g
mass of solvent = 12.3g
mass of solution = 1012.3g
molality = (1000g / molar mass) / (12.3g / 1000g) = 81.3 / molar mass
Next, we need to calculate the change in freezing point:
ΔT = 1.2∘C
Finally, we can use the freezing point depression constant of naphthalene to solve for the molar mass of the unknown substance:
Kf for naphthalene = 6.8∘C/m
ΔT = Kf × m
1.2 = 6.8 × (81.3 / molar mass)
molar mass = 68.4 g/mol
Therefore, the molar mass of the unknown substance is 68.4 g/mol.
Answer:
sulfuric acid
Explanation:
Sulfuric acid is a strong electrolyte.
- Strong electrolytes dissolve completely in water.
Acetic acid and Ammonia is a weak electrolyte.
- Weak electrolytes only partially dissolve in water.
- Hope this helps! If you need further explanation or more help please let me know; I would be glad to help anytime.
Answer:
sulfuric acid
Explanation:
b. a phosphate group.
c. a sugar group.
d. pyrimidines.
quick check answers: (you're welcomeee)
1. d
2. d
3. d
4. c
5. d
6. b
100% correct as i just finished it.
ANSWER: the original results have not been replicated consistently and reliably. | the only way for cold fusion to become a reliable theory is if scientists repeat this experiment is to make sure the results are repeatable. If a scientist cannot reproduce it anywhere in the world, then its deemed unaccepted as a theory.