The molecules AlCl3, CCl4, SCl2, and S3 have different geometries and bond angles due to the number of electron bonding pairs. As such, by increasing bond angles, the order is SCl2 < CCl4 < AlCl3 < S3.
The question asks us to sort the molecules AlCl3, CCl4, SCl2, and S3 by increasing bond angles about the central atom. To do this, we need to examine the geometry and the bond angles produced by the electronic arrangements of each molecule.
In AlCl3, the central atom, Al, has three bonded pairs of electrons resulting in a trigonal planar structure with bond angles of 120°. In CCl4, carbon is the central atom, and it forms four bonds with chlorine atoms, creating a tetrahedral structure. The bond angle for this molecule is approximately 109.5°. For SCl2, sulfur forms two bonds and has two lone pairs of electrons. The VSEPR model predicts a bent or V shape for the molecule, resulting in bond angles less than 109.5°. Lastly, S3 is a non-polar molecule with bond angles of 120°.
Therefore, the correct order of increasing bond angles would be SCl2 < CCl4 < AlCl3 < S3.
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Option A is correct.
A.The potential energy in the system is greatest at X.
A ball resting at the top of a hill will have greatest potential energy because when an object is at rest it tend to have greatest potential energy. When It moves from position X to Y the potential energy of the ball will decrease and its kinetic energy will increase.
Answer choices are listed below.
A.The potential energy in the system is greatest at X.
B.The kinetic energy in the system is greatest at X.
Answer: 1.848 g
Explanation: To calculate the moles, we use the equation:
....(1)
For ammonia:
Putting values in above equation, we get:
For the reaction:
By Stoichiometry of the reaction,
4 moles of ammonia combine with 3 moles of Oxygen
Thus 0.132 moles of ammonia will combine with= of oxygen
Thus ammonia is the limiting reagent as it limits the formation of product.
4 moles of ammonia produces 2 moles of nitrogen
0.132 moles of ammonia will produce= of nitrogen
Molar mass of nitrogen = 28 g/mol
Amount of nitrogen produced=
In the given chemical reaction, 8.00 x 10²² molecules of ammonia would produce 37.3 grams of nitrogen gas.
In this chemical reaction, every 4 molecules of ammonia (NH₃) produce 2 molecules of nitrogen gas (N₂). Given you have 8.00 x 10²² molecules of ammonia, this would produce (8.00 x 10²² / 2) x 2 = 8.00 x 10²² molecules of nitrogen gas, according to the reaction stoichiometry.
One molecule of nitrogen gas (N₂) has a molar mass of 28 g/mol. To convert molecules to moles, we need Avogadro's number (6.022 x 10²³ molecules = 1 mol). So, the number of moles of nitrogen gas is (8.00 x 10²² molecules / 6.022 x 10²³ molecules/mol) = 1.33 mole.
Now, by using the molar mass of nitrogen gas, we can find the mass. So, the mass of nitrogen gas = molar mass x moles = 28 g/mol x 1.33 mol = 37.3 grams.
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Enzymes for the breakdown of protein are present in the stomach.
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The answer to your questions is C. Stomach