Simplify the expression.
(1-5i)+(2+4i)
A. 3-i
B. -4+6i
C. 2i
D. -3+i

Answers

Answer 1
Answer: The answer is A. 3-i because 1+2=3 and -5-4=-1
Answer 2
Answer: A : 1+2 +4-5i = 3-i hahhahahhhhhhhhh

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Find the value of y when x equals 2 , -8x-5y=1

Answers

-8x - 5y = 1
when x = 2
-8(2) - 5y = 1
-16 - 5y = 1
5y = -16 - 1 = -17
y = -17/5

How do i solve and graph 5x- y \geq 5

Answers

one way is to make it into slope intercept form which is
y=mx+b
m=slope
b=y intercept or where the line will go though the y axis
treat the equal to or greater than sign as equals for now

5x-y=5
subtract y from both sides
5x=5+y
subtract 5
5x-5=y
put the sign back in
5x-5 ≥ y
reverse
y ≤ 5x-5

one way is to subsitute values and get values out so
if x=1 then
y≤5(1)-5
y≤0
(x,y)
(1,0)
(2,5)
(3,10)
(4,15)
(0,-5)

plot the points
then the ≤ sign
since ther is an underline, that means that the points are included so draw a solid line through the points

then figure out which side to shade on
the easy way is, is the point (0,0) a solution?
subsitute
0 ≤ 5(0)-5
0 ≤ -5
false so we shade the section that does not include the point (0,0) in it
the graph would look like this attachment


    (you have to put y alone {Ex: y = 12x + 3 (yis alone on one side)}



5x - y 
≥ 5       (subract 5x from each side)
-y ≥ -5x + 5   (divide - or -1 from each side)  Note: when you are dividing or multiplying anything negative the sign changes
≤ 5x - 5 <--- answer


As for graphing you take the equation and graph it normally, but with a slight change. since y is less than or equal to 5x - 5, you have to color on the spACE BELOW the graphed line.

see picture:




6) Two coastguard stations P and Q are 17km apart, with due East of P. A ship S is observed in distress on a bearing 048° fromP and 324 from Q. How far is the ship from each of the coastguard stations?

Answers

Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^(o) - 324^(o)

     = 036^(o)

Sum of angles in a triangle = 180^(o)

<P + <Q + <S = 180^(o)

048° + 036^(o) + <S = 180^(o)

84^(o) + <S = 180^(o)

<S  = 180^(o) -  84^(o)

    = 96^(o)

<S = 96^(o)

Applying the Sine rule,

(y)/(Sin P) = (x)/(Sin Q) = (z)/(Sin S)

(y)/(Sin P) = (z)/(Sin S)

(y)/(Sin 48^(o) ) = (17)/(Sin 96^(o) )

(y)/(0.74314) = (17)/(0.99452)

⇒ y = (12.63338)/(0.99452)

       = 12.703

y = 12.70 km

(x)/(Sin Q) = (z)/(Sin S)

(x)/(Sin 36^(o) ) = (17)/(Sin 96^(o) )

(x)/(0.58779) = (17)/(0.99452)

⇒ x = (9.992430)/(0.99452)

      = 10.0475

x = 10.05 km

Thus,

the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Help with these 2 questions please?? Check my answers. The height of a triangle is 13 in. less than its base. If the area of the triangle is 24 in2, what is the length of the base?

3 in.
10 in.<------
16 in.
21 in.




Madison hits a tennis ball with an initial velocity of 18 m/s straight up into the air. When she hits the ball, it is 1.2 m above the ground. Which equation can be used to find the time, t, it takes for the ball to reach the ground?

–4.9t2 + 18t + 1.2 = 0
–16t2 + 18t + 1.2 = 0<-------
–4.9t2 + 1.2t + 18 = 0
–16t2 + 1.2t + 18 = 0

Answers

1>
Let the base be "x"
According to the question, 

h = x - 13

A = 24 in sq.
Now,
Area of triangle =  (1)/(2)~b~h

24= (1)/(2)(x)(x-13)

24 *2= (x)(x-13)

48=   x^(2) - 13x

0=   x^(2) - 13x -48

Factorizing the equation,  x²  - 13x  -48, we get,

0=   x^(2)+3x - 16x -48

0=   x(x+3) - 16(x+3)

0=  (x + 3)(x-16)

NOW, using zero product property, we get,

Either,
x + 3 = 0 
     x = -3

Or,
x - 16 = 0
      x  = 16

Since, distance can't be negative, we have, x = 16 in.
So, the length of the base is 16 inches.

2>

umm...i don't know how to do it...can you post a picture of the same kind of (solved) question....i mean like an example


7|3y – 4|– 8 = 48
Please help!

Answers

Answer: y=4 or y= 4 over 3

Step-by-step explanation:

Answer:

y=4

Step-by-step explanation:

Is it possible to write a sequence that is both arithmetic and geometric

Answers

It is not possible to write a sequence that is both arithmetic and geometric.
An arithmetic sequence is:
a0, a0 + d, a0 + 2d, a0 + 3d, ...

An geometric sequence is:
a0, a0r, a0r2, a0r3, ...

So if the two are equal, we have:
a0 = a0,
a0 + d = a0r,
a0 + 2d = a0r2,
a0 + 3d = a0r3,
...

This can only be true if d = 0 and r =1 and only for the first three terms. It's a trivial sequence with only three elements which can't be necessarily classified as a sequence.