Here is how to do the question,
The Remainder Theorem starts with an unnamed polynomial p(x), where "p(x)" just means "some polynomial p whose variable is x". ... If you get a remainder, you do the multiplication and then add the remainder back in. For instance, since 13 ÷ 5 = 2 R 3, then 13 = 5 × 2 + 3. This process works the same way with polynomials.
Hope that helps!!!!
Answer:
Remainder Theorem starts with an unnamed polynomial p(x), where p(x) just means "some polynomial p whose variable is x". ... If you get a remainder, you do the multiplication and then add the remainder back in, For instance, since 13 ÷ 5 = 2 R 3, then 13 = 5 × 2 + 3. This process works the same way with polynomials
-3x + 5x -2 > 8x - 7 -9x
To get the minimum amount of fencing, the farmer should use the equation P = x + 2*(2000/x), representing the total fence length, where x is the length of the fence parallel to the river, and solve this to find the minimum.
The problem involves resolving a mathematical problem using functions in optimization. The farmer's goal is to minimize the fencing used which means minimizing the perimeter of the pen. Considering that one side of the pen will be a river, we are essentially looking for the dimensions of a rectangle (with one side along the river) which uses the least amount of fencing. Let's say the length of the fence parallel to the river is x, and the length of the fence perpendicular to the river is y.
Since area (A) is given by A = x*y, which must be 2,000 m2, we can rewrite y equation in terms of x as y = 2,000/x. The total fence length (perimeter, P) is calculated as P = x + 2y and substituting the new equation for y, we get P = x + 2*(2000/x), which is the function that the farmer needs to optimize in order to use the least amount of fencing.
#SPJ12
To the nearest square inch, what is the area of the figure?
309
118
64
49
Answer:
309in²
Step-by-step explanation:
Area of an octagon is expressed as;
A=2(1+√2)a²
a is the side length of the octagon
Given
a = 8
Substitute into the formula
A = 2(1+√2)(8)²
A = 2(1+√2)(64)
Expand
A = 2(64+64√2)
A = 128+128√2
A = 128+128(1.414)
A = 128+181.01
A = 309in²
Hence the area of the octagon is 309in²