Answer: 9.13g NO
Explanation:
First, I list what I know, which is the values of STP, the volume, the constant R, and the molar mass of NO; I also include what I'm looking for, which is n, the number of moles of NO.
STP = 273.15K, 1 atm
P = 1 atm
V = 6.82L
R = 0.0821 L*atm/mol*K
T = 273.15K
n = ?
NO mass: 30.01 g/mol
Then, I use the ideal gas law, PV = nRT, to find the number of moles of NO:
(1 atm)(6.82 L) = n()(273.15K)
(1 atm)(6.82 L) = n()
(1 atm)(6.82 L) / () = n => divided both sides by 22.4L*atm/mol
n = 0.304 mol NO
Then, I use the molar mass of NO, 30.01 g/mol, to convert from mol NO to g NO:
g NO = 0.304 mol NO()
= 9.13 g NO
I hope this helps! :)
dioxide.
please show work thank you
The percentage yield of the reaction has been 46.74%.
Percentage yield can be given as the ratio of the actual yield to the theoretical yield.
For the theoretical yield, the balanced equation will be:
Thus, 2 moles of ZnS will give 2 moles of ZnO.
The moles of 46.5 g ZnS:
Moles =
ZnS =
ZnS = 0.477 mol
The moles of 13.3 grams Oxygen:
Oxygen =
Oxygen = 0.415 mol.
The moles of 18.14 grams ZnO:
ZnO =
ZnO = 0.222 mol
According to the balanced chemical equation,
2 moles ZnO = 2 moles ZnS
0.222 mol ZnO = 0.222 mol ZnS
2 moles ZnO = 3 moles Oxygen
0.222 mol ZnO = 0.334 mol of Oxygen
Since, both the reactants are in enough concentration,
The theoretical yield can be calculated with any of the reactants. The theoretical yield of ZnO from 46.5 grams of ZnS can be given as:
1 mole ZnS = 1 mol ZnO
0.477 mol of ZnS = 0.477 mol of ZnO.
The mass of 0.477 mol of ZnO:
Mass = moles molecular weight
Mass of ZnO = 0.477 81.38
Mass of ZnO = 38.818 grams.
The theoretical yield of ZnO = 38.818 g.
The actualyield of ZnO = 18.14 g.
Percentage yield =
Percentage yield = 46.74 %
The percentage yield of the reaction has been 46.74%.
For more information about the percentage yield, refer to the link:
a. 7.30 g
b. 93.3 g
c. 146 g
d. 150 g
e. 196 g
The question tackles stoichiometry, a Chemistry concept used to calculate reactant or product amount. Given 2 moles of H2SO4 and 2.56 moles of NaCl, the H2SO4 is limited, resulting in 4 moles of HCl. The weight of 4 moles of HCl is 146 g, thus, the answer is c. 146 g.
The subject of this question is stoichiometry, a method used in Chemistry to calculate the amount of reactants or products in a particular chemical reaction. According to the balanced equation, 2 moles of NaCl react with 1 mole H2SO4 to yield 2 moles of HCl. Meaning, 1 mole of H2SO4 can only react effectively with 2 moles NaCl. However, we have 2.56 mol of NaCl. This means that the H2SO4 is the limiting reagent. Thus, 2 mol H2SO4 will yield 4 mol of HCl (since it's 2:2 ratio).
The molecular weight of HCl is 36.5 g/mol. Therefore, the weight of 4 moles of HCl is 4 mol * 36.5 g/mol = 146 g. Thus, the correct answer is c. 146 g.
#SPJ11
c. a change in temperature
d. a change in density
e. a change in structure
Answer: it is easily magnetized
Explanation:
A) What do whale sharks eat?
B) How big is the average whale shark’s mouth?
C) Does a whale shark like having a large mouth?
D)What happens to the water that enters a whale shark’s mouth?
Chemistry Honors College level
10th grader
Answer:
The nonscientific question about whale sharks is
C) Does a whale shark like having a large mouth?
This question asks for the subjective preference of a whale shark, which cannot be determined scientifically since we cannot directly communicate with the animal. Scientific questions are typically based on observable facts and measurable data.
Explanation:
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