Think about multiplying each speed by a factor to calculate kinetic energy at that speed.Is there a common factor that works for every speed? If so, what’s this factor?

Answers

Answer 1
Answer:

Answer:

To calculate kinetic energy, you use the formula KE = 0.5 * m * v^2, where "m" is the mass and "v" is the speed. There isn't a common factor that works for every speed; the factor you use is 0.5. This formula is derived from the principles of classical mechanics and doesn't change with speed; it's a fundamental equation for calculating kinetic energy.


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Scientists are working on a new technique to kill cancer cells by zapping them with ultrahigh-energy (in the range of 1012W) pulses of light that last for an extremely short time (a few nanoseconds). These short pulses scramble the interior of a cell without causing it to explode, as long pulses would do. We can model a typical such cell as a disk 5.0μm in diameter, with the pulse lasting for 4.0 ns with an average power of 2.0×1012W. We shall assume that the energy is spread uniformly over the faces of 100 cells for each pulse. (a) How much energy is given to the cell during this pulse? (b) What is the intensity (in W/m2) delivered to the cell? (c) What are the maximum values of the electric and magnetic fields in the pulse?

Answers

Answer:

a. 80 J/cell b. 1.02 × 10²¹ W/m² c. 8.77 × 10¹¹ V/m d. 2.92 × 10³ T

Explanation:

a. We know that energy E = Pt where P = power and t = time

The total energy delivered to all the 100 cells is E = average power × time

average power = 2 × 10¹² W and time = 4 ns = 4 × 10⁻⁹ s

E = 2 × 10¹² W × 4 × 10⁻⁹ s = 8 × 10³ J

The energy per cell E₁ = E/100 = 8 × 10³ J/100 = 80 J/cell

b. Intensity, I = P/A where P = power per cell = 2 × 10¹² W/100 = 2 × 10¹⁰ W and A = area = πr². Since the cell is modeled as a disk of diameter d = 5.0μm, r = d/2 = 5.0 μm/2 = 2.5 μm = 2.5 × 10⁻⁶ m

I = P/A = P/πr² = 2 × 10¹⁰ W/π(2.5 × 10⁻⁶ m)² = 1.02 × 10²¹ W/m²

c. The intensity I = E²/2cμ₀ where E = maximum value of electric field, c = speed of light = 3 × 10⁸ m/s and μ₀ = 4π × 10⁻⁷ H/m

E = √(I2cμ₀) = √(2 × 1.02 × 10²¹ W/m² × 3 × 10⁸ m/s × 4π × 10⁻⁷ H/m) = 8.77 × 10¹¹ V/m

The maximum magnetic field B is gotten from E/B = c

B = E/c = 8.77 × 10¹¹ V/m/3 × 10⁸ m/s  = 2.92 × 10³ T

At what speed v will the length of a 1.00 m stick look 13.7 % shorter (86.3 cm )Using formula L=Lp sqrt 1-v^2/c^2

Answers

L= Lp - 13.7*Lp/100 = Lp-0,137Lp = 0,8613Lp

⇒L/Lp = 0.8613

From the formula above L/Lp = √(1-v^2/c^2)

(L/Lp)^2 = 1 - (v^2/c^2)

v^2/c^2 = 1 - (L/Lp)^2

v/c = √[1 - (L/Lp)^2]

v = c √[1-(L/Lp)^2]

v =c√[1-0.8613^2] = 0.508c

In the vacumm speed of light, c,  is approx 300,000,000 m/s

v =0.508 (300,000,000m/s) =152,400,000 m/s

Please, let me know if this helped you.

Does gravity have an effect on the potential difference of a battery?

Answers

Answer: The correct answer is "No".

Explanation:

Gravity: It is the force which causes object to fall on the earth. It is the force which attracts bodies towards each other.

Potential difference: It is defined as the potential acting between the two points. The work done in moving the unit positive charge from one location to the another location.

The potential difference in battery is caused by the electrodes. There are two terminals in battery: Negative terminal which is at lower potential and Positive terminal which is at higher potential. It forces the electrons to flow in the circuit which constitutes the current.

The gravity and the potential difference have no relation between them.

Therefore, gravity have no effect on the potential difference of a battery.

Final answer:

Gravity does not have a direct role in determining the potential difference in a battery. It is the chemical reaction inside the battery that generates the potential difference, which transforms into electric potential energy when the battery is connected to a load. Analogies exist between gravitational and electric potential energies, but they function independently of one another.

Explanation:

No, gravity does not have a direct effect on the potential difference of a battery. The potential difference in a battery is generated via a chemical reaction within the battery itself that separates charge. The energy stored in the battery is primarily presented in the form of chemical potential energy, which transforms into electric potential energy when the load is connected.

This mechanism is independent of gravitational forces. To illustrate this, let's consider the following analogy: the potential energy of a raised hammer is stored in Earth's gravitational field. If the gravitational field were to disappear, the hammer would have no potential energy. Similarly, in the battery, if no electric field existed between the plates, no energy would be stored between them. This analogy showcases that the electrical potential in the battery does not depend on gravity. However, it would be misleading to interpret this as a correlation between the two. The force acting in a battery is electromagnetic, not gravitational.'

On another note, a similar analogy exists between gravitational potential energy and electric potential energy. On one hand, the gravitational potential energy increases as an object is lifted higher in Earth's gravitational field. On the other hand, the electric potential energy increases as the positive charge gets farther from the negative charge in the battery. The acceleration due to gravity changes as we move away from Earth, requiring adjustments in the expressions for gravitational potential energy. However, these factors do not impact the potential difference in a battery.

Learn more about Gravity and Battery Potential here:

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Select the type of volcanoes that frequently erupt violently?A. Cinder cone

B. Stratovolcano

C. Shield volcano

* it’s not B

Answers

the correct answer would be

C

A pedestrian moves 6.00 km east and then 13.0 km north. Find the magnitude and direction of the resultant?

Answers

Magnitude = √(6² + 13²)  = √205  =  14.32 KM  (rounded)

Direction east of north = tan⁻¹ (6/13)  =  24.8° east of north

Gaya 7,5 dikerjakan pada masa sebesar 3 kg sehingga kelajuannya berubah dari 65 cm/s menjadi 15 m/s maka waktu yang dibutuhkan adalah

Answers

F=7,5 N
m = 3kg
F=m.a
7,5=3.a
a=7,5/3
a=2,5 m/s^2

Vo = 65cm/s -> 0,65m/s
Vt = 15m/s
t..?

Vt=Vo+a.t
15 = 0,65 + 2,5.t
14,35=2,5.t
t=5,74 secon