the maximum characteristic x-ray photon energy comes from the capture of a free electron into a k shell vacancy. what is this photon energy in kev for polonium assuming the free electron has no initial kinetic energy?

Answers

Answer 1
Answer:

The photon energy is 75 keV (kilo-electron volts) for polonium, assuming the free electron has no initial kinetic energy.

The maximum characteristic x-ray photon energy from the capture of a free electron into a K-shell vacancy is equal to the difference in binding energies between the K-shell and L-shell in the atom.

For polonium (Po), the atomic number is 84, which means it has 84 electrons. The K-shell of polonium is filled with 2 electrons, and the L-shell is filled with 8 electrons.

The K-shell binding energy for polonium can be found in a table of atomic data to be around 88 keV. The L-shell binding energy can also be found in the same table to be around 13 keV.

Therefore, the maximum characteristic x-ray photon energy from the capture of a free electron into a K-shell vacancy in polonium is:

E = (K-shell binding energy) - (L-shell binding energy)

= 88 keV - 13 keV

= 75 keV

To know more about binding energies refer here

brainly.com/question/30073915#

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A solid aluminum cube has sides each of length L . A second cube of the same material has sides four times the length of the first cube; i.e., 4 L . Compared to the first cube, the total surface area of the second cube is 1. twenty-seven times the first cube. 2. sixteen times the first cube. 3. sixty-four times the first cube. 4. eight times the first cube. 5. twenty-four times the first cube. 6. two times the first cube

Answers

Answer:

Option (2): Sixteen times the first cube

Explanation:

Surface \:  Area \:  of  \: Cube = 6 {a}^(2)

(T.S.A \: of \: larger \: cube)/(T.S.A \: of \: smaller \: cube)  =  \frac{6 * 16 {l}^(2) }{6 *  {l}^(2) }  = 16

When the linear dimensions of a solid are multiplied by ' R ', the surface area of all or any part of it increases by R² , and the volume of all or any part of it increases by R³ .

If the sides of the second cube are 4 times the sides of the first one, then the second cube has (4²) = sixteen times the surface area of the first one (2), and it has (4³) = 64 times the volume of the first one.

Why does a siren on an ambulance sound louder as it approaches you?

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Answer:

As the ambulance approaches you, the distance between the source of the waves and the observer decreases. Consequently, the siren sounds more shrill as the pitch of the wailing siren 'sounds' higher than its original value, as sound waves reach you 'more frequently'.

Explanation:

hope it helps :)

Answer:As the ambulance approaches you, the distance between the source of the waves and the observer decreases. Consequently, the siren sounds more shrill as the pitch of the wailing siren ‘sounds’ higher than its original value, as sound waves reach you ‘more frequently’

Explanation:

Is there a benefit to cooking in a regular oven compared to a convection oven? Why??

Answers

Yes there is a benefit it is that a regular oven is faster at cooking because it can go to higher tempatures
convectional oven has a lower rate of acceleration, why regular oven has a faster rate. 

A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7 1010 m (inside the orbit of Mercury), at which point its speed is 9.5 104 m/s. Its farthest distance from the Sun is far beyond the orbit of Pluto. What is its speed when it is 6 1012 m from the Sun? (This is the approximate distance of Pluto from the Sun.)

Answers

Answer:

58515.9 m/s

Explanation:

We are given that

d_1=4.7* 10^(10) m

v_i=9.5* 10^4 m/s

d_2=6* 10^(12) m

We have to find the speed (vf).

Work done by surrounding particles=W=0 Therefore, initial energy is equal to final energy.

K_i+U_i=K_f+U_f

(1)/(2)mv^2_i-(GmM)/(d_1)=(1)/(2)mv^2_f-(GmM)/(d_2)

(1)/(2)v^2_i-(GM)/(d_1)+(GM)/(d_2)=(1)/(2)v^2_f

v^2_f=2((1)/(2)v^2_i-(GM)/(d_1)+(GM)/(d_2))

v_f=\sqrt{2((1)/(2)v^2_i-(GM)/(d_1)+(GM)/(d_2))}

Using the formula

v_f=\sqrt{v^2_i+2GM((1)/(d_2)-(1)/(d_1))}

v_f=\sqrt{(9.5* 10^4)^2+2* 6.7* 10^(-11)* 1.98* 10^(30)((1)/(6* 10^(12))-(1)/(4.7* 10^(10)))

Where mass of sun=M=1.98* 10^(30) kg

G=6.7* 10^(-11)

v_f=58515.9 m/s

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Answers

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Answers

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