A person runs 400 meters in a straight line. Determine their distance and displacement. Is the distance equal to the displacement for a person that runs 2.5 times around a circular track?

Answers

Answer 1
Answer:

Answer:

their distance and displacment are both 400 meters. and No distance and displacement are not equal for a person who runs 2.5 times a circular track.

Explanation:

if you run in a ircle you are coming back to the starting poing ad remember distane is the total length travlled while displacement is the final- initial length


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Answers

It's called Electrophily, or electron affinity.
Insulator 

Insulator tendency to hold onto electrons 

What Is Solar Radiation?

Answers

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Classical physics is a good approximation to modern physics under certain circumstances. What are they?

Answers

Answer and Explanation:

In classical physics we study about macroscopic objects and in modern physics we study about microscopic objects but under some circumstances classical physics is a approximation to modern physics such as

  • The object must be microscopic but they should be large enough so that we can see that through a microscope
  • The speed of the object should be very less it should be about 1 % of the speed of the light
  • They should be involved with very week gravitational field

Answer:

Classical physics is a good approximation to modern physics under these certain circumstances: Matter must be moving at speeds less than about 1% of the speed of light, the objects dealt with must be large enough to be seen with a microscope, and only weak gravitational fields, such as the field generated by the Earth, can be involved.

Explanation:

78. The initial velocity of a projectile has a horizontal
component equal to 5 m/s and a vertical component
equal to 6 m/s.
At the highest point of the projectile's flight, what is (a) the horizontal component of its
velocity and
(b) the vertical component of its velocity?
Explain.

Answers

Final answer:

The horizontal component of a projectile's velocity remains constant throughout its flight. Hence, at the highest point, its value is the same as the initial, 5 m/s. The vertical component, on the other hand, becomes zero at the highest point.

Explanation:

For a projectile, the horizontal component of motion and the vertical component of motion are independent. Therefore, the horizontal component of velocity remains constant throughout the flight as long as there is no air resistance. Hence, at the highest point of a projectile's flight, the horizontal velocity (a) remains the same, i.e., 5 m/s.

However, for the vertical component, it is subjected to the acceleration due to gravity. At the highest point, the vertical component of velocity (b) becomes zero, because it has momentarily stopped before changing direction and accelerating downwards.

Learn more about Projectile Motion here:

brainly.com/question/20627626

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Answer:Consider again the cannonball launched by a cannon from the top of a very high cliff. Suppose that the cannonball is launched horizontally with no upward angle whatsoever and with an initial speed of 20 m/s. If there were no gravity, the cannonball would continue in motion at 20 m/s in the horizontal direction. Yet in actuality, gravity causes the cannonball to accelerate downwards at a rate of 9.8 m/s/s. This means that the vertical velocity is changing by 9.8 m/s every second. If a vector diagram (showing the velocity of the cannonball at 1-second intervals of time) is used to represent how the x- and y-components of the velocity of the cannonball is changing with time, then x- and y- velocity vectors could be drawn and their magnitudes labeled. The lengths of the vector arrows are representative of the magnitudes of that quantity. Such a diagram is shown below.

Explanation: i hoped that helped!

Karen shouts across a canyon and hears an echo 7.5 s later. how wide is the canyon? the speed of sound is 343 m/s. answer in units of m.

Answers

After Karen shouts, the sound wave of her voice travels across the canyon, it hits the walls, and then it comes back to Karen in a total time of t=7.5 s. If we call L the distance between Karen and the other side of the canyon (so, L is the width of the canyon), it means that the sound wave covers a distance of S=2L in this time.
Since the wave moves by uniform motion, we can use the usual relationship between space, time and velocity:
v= (S)/(t)= (2L)/(t)
where v=343 m/s is the speed of sound. Using this number, we can find L from the previous equation:
L= (vt)/(2)= ((343 m/s)(7.5 s))/(2)=1286 m
So, the canyon is 1286 meters wide.

A container filled with gas has a volume of 185 mL and a pressure of 310 mm Hg. The desired new volume is 74.0 mL. What is the required new pressure? 124 mm Hg 44 mm Hg 775 mm Hg 0.00129 mm Hg

Answers

The answer is 124 mm hg