Answer:
a. p-o²nc⁶h⁴ch(oh)ch
Explanation:
The alcohol that is dehydrated most easily with conc. H₂SO₄ is p-C1C₆H₄CH(OH)CH₃.
The alcohol that is dehydrated most easily with conc. H²SO⁴ is p-C1C⁶H⁴CH(OH)CH³. This alcohol is tertiary, meaning it has three alkyl groups attached to the carbon atom containing the hydroxyl group. Tertiary alcohols are more easily dehydrated compared to primary and secondary alcohols because the carbon atom attached to the hydroxyl group is more stable due to the presence of the alkyl groups.
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Here's your asnwer.
50
Answer:
posible mente es una equivocacion porque dijo que estaban refriados y les dió una medicina para la tos
b. Carbon is ranked seventeenth in abundance in Earth's crust.
c. Carbon is readily found combined and uncombined in nature.
d. Carbon is found in all living matter and in common fuels including coal.
All the statements are true about carbon except option a. Carbon is not a major component of inorganic molecules.
Carbon is 6th element in periodic table. It is in 14th group and is a non-metal or gas. Carbon is present in all living matter and in common fuels including coal.
Carbon can be readily found in combined or non-combined state. Carbon is the major component of organic molecules and not that of inorganic molecules.
Organic molecules are hydrocarbons or their derivatives whose backbone is carbon chain. Therefore, option a is not true about carbon.
To learn more about carbon, refer the link below:
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Answer: It is True
Explanation:Because Ionization energy refers to the amount of energy required to remove an electron from an atom.
changes from 53.0 atm to 35.2
atm, the temperature changes
from
°C to 12.0°C.
Please help I will give brainliest
Answer:
To determine the relationship between pressure and temperature in this scenario, we can use the ideal gas law.
The ideal gas law states that PV = nRT, where P represents pressure, V represents volume, n represents the number of moles of gas, R is the ideal gas constant, and T represents temperature in Kelvin.
Since we only have the initial and final pressures and temperatures, we can compare them using the ideal gas law equation by setting up the following ratio:
(P₁T₁) / (P₂T₂) = (V₁n₁R) / (V₂n₂R)
Since the volume, number of moles, and gas constant remain constant, we can simplify the equation:
(P₁T₁) / (P₂T₂) = 1
Now, we can substitute the given values into the equation:
(53.0 atm * T₁) / (35.2 atm * 12.0°C) = 1
To solve for T₁, we need to convert 12.0°C to Kelvin by adding 273.15:
(53.0 atm * T₁) / (35.2 atm * (12.0 + 273.15) K) = 1
Simplifying the equation further:
(53.0 atm * T₁) / (35.2 atm * 285.15 K) = 1
Now, we can solve for T₁:
(53.0 atm * T₁) = (35.2 atm) * (285.15 K)
Dividing both sides of the equation by 53.0 atm:
T₁ = (35.2 atm * 285.15 K) / 53.0 atm
Calculating the numerical value:
T₁ ≈ 189.5 K
Therefore, when the pressure changes from 53.0 atm to 35.2 atm, the temperature changes from approximately 12.0°C to 189.5 K.