The sun rises between two mountain peaks. The edge of one mountain peak (right) forms a tangent with the sun. The other does not. What is the measure of the arc of the sun that is showing given that y=113º. Note: you are solving for the arc measure, not the arc length. Round your answer to one decimal place, if necessary.
The sun rises between two mountain peaks. The edge of - 1

Answers

Answer 1
Answer:

Answer:

226°

Step-by-step explanation:

According to the Tangent and Intersected Chord Theorem, if a tangent and a chord intersect at a point on a circle, then the measure of each angle formed is one-half the measure of its intercepted arc.

Therefore, if y = 113°, then y is one-half of the intercepted arc x.:

y=(1)/(2)m\overset\frown{x}

2y=m\overset\frown{x}

2(113^(\circ))=m\overset\frown{x}

m\overset\frown{x}=226^(\circ)

Therefore, the measure of arc x is 226°.

Answer 2
Answer:

Check the picture below.


Related Questions

What is the value of 3-(-2)
Suppose the diameter of a circle is 6. What is its circumference
For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0. graph of f of x equals 0.5 to the x power, minus 6.
1. Complete the tables of values below for graphing the secant and cotangent functions. You can type “U” for an undefined value. Use exact values with fractions and square roots, not the decimal approximations. For example, use 3/2 rather than 0.866 (pictures attached) 2. Graph the secant graph for 0 ≤ x ≤ 2π. Graph the cotangent graph for 0 ≤ x ≤ 2π. (don't need these pictures I have them) 3. Indicate whether each of the three reciprocal functions (cosecant, secant, and cotangent) is a periodic function. If so, state the period of each. 4. List the domain and range for the secant and cotangent functions. (Use "pi" for π.) 5. Compare the graphs of the cosecant and secant functions. How are they different? How are they similar?
Which quadratic function has one real solution?A.0 = 2(x + 7)(x – 5) B.0 = (x – 3)(x – 3) C.0 = 2.4(x – 2)(x + 2) D.0 = (x – 2)(x – 1)

Using the fact that cos(52) = 0.6157, find the measure of angle B if sin(B) = 0.6157.

Answers

Answer:  B = 38

===============================================

Work Shown:

If cos(A) = sin(B), then A+B = 90, where A & B are both acute angles in degree form.

In this case, A = 52, so,

A+B = 90

B = 90-A

B = 90-52

B = 38

Telling us that

cos(A) = cos(52) = 0.6157

sin(B) = sin(38) = 0.6157

cos(52) = sin(38)

There are 2,100 bacteria in a circular petri dish. The dish has a radius of 40 millimeters. What is the approximate population density? (Use 3.14 for π) Area of a circle = πr2 0.02 bacteria per square millimeter 0.42 bacteria per square millimeter 2.39 bacteria per square millimeter 52.5 bacteria per square millimeter

Answers

The population density is 0.418 bacteria per mm².

What is Area of Circle?

A circle's area is the area that it takes up in a two-dimensional plane.

The  formula for area of circle is, A = πr²,  where r is the radius of the circle. The unit of area is the square unit, such as m², cm², etc.

Given:

Radius= 40 mm

So, Area of petri dish = πr²

                                    = 3.14x(40 mm)²

                                    = 3.14 x 1600 mm²

                                    = 5024 mm²

and, Population Density

= 2100 / 5024

= 0.418 bacteria per mm²

Hence, the population density is 0.418 bacteria per mm².

Learn more about area of circle here:

brainly.com/question/28642423

#SPJ6

Population Density = # bacteria/area

Area = πr^2
= 3.14•(40 mm)^2
= 3.14•1600 mm^2
= 5024 mm^2

Pop Density = 2100 / 5024
= 0.418 bacteria per mm^2

The answer is 0.42 bacteria per square mm

A tree casts a 25 foot shadow. At the same time of day, a 6 foot man standing near the tree casts a 9 foot shadow. What is the approximate height of the tree to the nearest foot? A) 16 feet
B) 17 feet
C) 18 feet
D) 19 feet

Answers

Answer:

Answer is option b

17 feet.

Step-by-step explanation:

Given that A tree casts a 25 foot shadow. At the same time of day, a 6 foot man standing near the tree casts a 9 foot shadow.

for man actual height = 6 foot

Shadow = 9 foot

At a particular time, the height/shadow ratio would be constant

Hence 6/9 =x/25

Or x = 25(6)/9

x=16.67feet

Rounding off x=17 feet

ratio of object to shadow = 6/9 = x/25 (where x is the height of the tree)
x = (6 * 25)/9 = 16.67feet

x = approx. 17 feet

12, 6, 7, 11, 11, 9, 13, 16, 10. What is the interquartile range of the data set?

Answers

first put the numbers in order
6,7,9,10,11,11,12,13,16

Q1 = (7 + 9) / 2 = 16/2 = 8
Q2 (median) = 11
Q3 = (12 + 13) / 2 = 25/2 = 12.50

Interquartile range (IQR) = Q3 - Q1 = 12.50 - 8.00 = 4.5

What's another way to write (6+7)x?

Answers

i think 6x+7x because i think u distribute 
You can write it as 13x. I hope this helps!

6+7=13               (13)x=13x

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.True or False?

Answers

With the center and the point (-6,2) you can deduce the equation of the circle

(x-xo)^2 + (y-yo)^2 = r^2

(x+3)^2 + (y-4)^ = r^2

r^2 is otained from the center and the point (-6,2)

r^2 = (-6 -(-3))^2 + (2-4)^2 = (-6+3)^2 + (-2)^2 = (-3)^2 + 4 = 9 + 4 = 13.

Then the equation of the circle is

 (x+3)^2 + (y-4)^ = 13

Now we subsitute the point (10,4) into that equation and see whether it belongs to it:

(10+3)^2 + (4-4)^2 = 13^2

13^2 ≠ 13, so the point does not belong to the equation.