The data recorded by Ben shows the attendance log of his classmates over a given period of time.
This refers to a simple chart that resembles a histogram that is used to represent small data.
Hence, we can see that because Ben tracked the attendance of the class over a given time period with the frequency on a frequency table, a sample of a dot plot has been provided below,
Read more about dot plots here:
#SPJ2
Answer: took the
Step-by-step explanation:
Answer:
b7 or b5
Step-by-step explanation:
6b-141 or 2b+111
+1 to both sides to get 6b42
then divide both sides by 6 to get b7
then for the other side you -1 by both sides to get 2b10
then divide both sides by 2 to get b5
then your final answer would be b7 or b5.
Answer:
Total cost of the article altogether is $42.75 .
Step-by-step explanation:
As given
An article retails for $37.50.
The city sales tax is 6%, and the federal excise tax is 8%.
6% is written in the decimal form
= 0.06
Price of city sales tax = 0.06 × Article cost
= 0.06 × 37.50
= $ 2.25
8% is written in the decimal form
= 0.08
Price of federal excise tax = 0.08 × Article cost
= 0.08 × 37.50
= $ 3
Thus
Total cost of the article altogether = Article cost + Price of city sales tax + Price of federal excise tax
Putting all the values in the above
= $ 37.50 + $2.25 + $3
= $ 42.75
Therefore the total cost of the article altogether is $42.75 .
True
False
The absolute maximum and minimum of a function on a given interval can be found by calculating the function's critical points and evaluating the function at these points and the interval endpoints, then comparing these values.
In order to find the absolute maximum and absolute minimum values of a function on a given interval, you must first find the critical points of the function within the interval. Critical points occur where the derivative of the function is equal to zero or is undefined. In this case, the derivative of f(t) = 9t + 9 cot(t/2) is f'(t) = 9 - (9/2) csc2(t/2). Set this to zero and solve for t to find the critical points. Additionally, the endpoints of the interval, π/4 and 7π/4, could be the absolute maximum or minimum, so these should be evaluated as well. Once you have found the values of the function at these points and the endpoints, compare them to determine the absolute maximum and minimum values.
#SPJ12
To find the absolute maximum and minimum values of a function, we find the critical points and endpoints. Evaluating the function at these points gives the maximum and minimum values.
To find the absolute maximum and absolute minimum values of a function on a given interval, we need to find the critical points and endpoints of the interval.
To find the critical points of f, we need to find where the derivative of f is equal to zero or undefined. The derivative of f(t) = 9t + 9cot(t/2) is f'(t) = 9 - 9csc^2(t/2).
Setting f'(t) = 0, we have 9 - 9csc^2(t/2) = 0. Solving this equation, we get csc^2(t/2) = 1, which means sin^2(t/2) = 1. This gives us sin(t/2) = ±1. The critical points occur when t/2 = π/2 or t/2 = 3π/2. Solving for t, we get t = π or t = 3π as the critical points.
The endpoints of the interval are π/4 and 7π/4.
Now we evaluate the function f at the critical points and endpoints:
From these evaluations, we can see that the absolute maximum value occurs at t = 7π/4 and is approximately 46.607, while the absolute minimum value occurs at t = π/4 and is approximately 6.566.
#SPJ11