For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0. graph of f of x equals 0.5 to the x power, minus 6.
Answers
The average rate of change will be negative 7 / 3.
How to find the average rate of change of something?
Let the thing that is changing be y and the thing with which the rate is being compared is x, then we have the average rate of change of y as x changes as:
Average rate = (y₂ - y₁) / (x₂ - x₁)
The exponential function is given below.
f(x) = (0.5)ˣ - 6
Then the average rate of change will be
Average rate = [f(0) - f(-3)] / [0 - (-3)]
Average rate = [(0.5⁰ - 6) - (0.5⁻³ - 6)] / 3
Average rate = [1 - 6 - 8 + 6] / 3
Average rate = - 7 / 3
More about the average rate of change link is given below.
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I hope that this helps :) :) :)
Answer:
It would be the...
Step-by-step explanation:
Average rate of change = -1/3
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Brian bought beverages for his coworkers. One day he bought 3 lemonades and 4 iced teas for $12.00. The next day he bought 5 lemonades and 2 iced teas for $11.50. Find the cost of 1 lemonade and 1 iced tea, to the nearest cent.
Answers
A. h = 3 m; r = 3 m
B.h = 4.23 m; r = 5 m
C.h = 15 m; r = 6 m
D.h = 33.75 m; r = 2 m
Answers
Cone-shaped filter: height = 4m ; diameter = 9m
cylinder: one full cone-shape filter fills 1/5 of the cylinder
volume of the cone = π r² h/3 = 3.14 * (4.5m)² * 4m/3
V = 3.14 * 20.25m² * 1.33m
V = 84.57 m³
84.57 m³ ÷ 1/5 = 84.57 m³ * 5 = 422.85 m³ volume of the cylinder
Volume of cylinder = π r² h
Choice A: V = 3.14 * (3m)² * 3m = 3.14 * 9m² * 3m = 84.78 m³
Choice B: V = 3.14 * (5m)² * 4.23m = 3.14 * 25m² * 4.23m = 332.10 m³
Choice C: V = 3.14 * (6m)² * 15m = 3.14 * 36m² * 15m = 1695.60 m³
Choice D: V = 3.14 * (2m)² * 33.75 m = 3.14 * 4m² * 33.75m = 423.90 m³
The closest answer is Choice D. height = 33.75 m ; radius = 2 m
Answers
Cross multiply: 36*?= 108*100
⇒ ?= 108*100/36= 300
108 is 36% of 300.
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Answers
After ten years, Tamora will have spent $6.496.76 on interest.
What is Compound interest?
Compound interest is the interest on savings calculated on both the initial principal and the accumulated interest from previous periods.
Given, Tamora has just graduated from college. When she entered college four years ago, she took out a $9,100 subsidized Stafford loan, which has a duration of ten years. The loan has an interest rate of 5.4%, compounded monthly.
The total amount of interest to be paid can be expressed as;
A={P}
where;
A = Total amount of interest
P = principal amount of the loan
r = annual interest rate
n = number of compounding periods in a year
t=number of years
In our case;
P=$9,100
r=5.4%=5.4/100=0.054
n=12
t=10 years
Replace the values and solve
A=9,100{(1+0.054/12)^(12×10)}-9,100
A=9,100{(1.0045)^120}-9,100
A=6,496.7575
The sum has been rounded to the closest penny. The equivalent of rounding to the nearest decimalplace is 1/100=0.01.
A=$6,496.76
Tamora will have paid $6.496.76 in interest overall after ten years.
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Answer:
The total interest amount that Tamora will have paid in 10 years=$6.496.76
Step-by-step explanation:
Step 1: Express the formula for calculating total amount of interest
The total amount of interest to be paid can be expressed as;
A={P(1+r/n)^nt}-P
where;
A=total amount of interest
P=principal amount of loan
r=annual interest rate
n=number of compounding periods in a year
t=number of years
In our case;
P=$9,100
r=5.4%=5.4/100=0.054
n=12
t=10 years
Step 2: Replace the values and solve
A=9,100{(1+0.054/12)^(12×10)}-9,100
A=9,100{(1.0045)^120}-9,100
A=6,496.757596
The amount rounded off to nearest cent 1/100=0.01 is the same as rounding off to nearest decimal places
A=$6.496.76
The total interest amount that Tamora will have paid in 10 years=$6.496.76
Answers
A quadrant is the group, or side of the graph.
There are 4 quadrants on a normal graph.
Below (in picture) is each one.