b)It contains particles that can settle out.
C)It has nutrients that are dissolved in its liquid portion.
D)It contains particles that mix on a molecular level.
Answer:
I think the best answer is b
Explanation:
I think the best answer is b
Among carbon, copper, chlorine, and calcium, copper has the highest density at standard temperature and pressure.
The element with the greatest density at standard temperature and pressure (STP) among the options given (carbon, copper, chlorine, calcium) is copper. Density, in elemental terms, is determined by the amount of mass packed in a given volume. Copper (Cu) has a density of approximately 8.96 g/cm^3 at STP, which is greater than that of carbon, chlorine, and calcium.
For comparison:
Carbon(C) has a significantly lower density at about 2.26 g/cm^3, chlorine (Cl) is a gas at STP and has a very low density of 0.003214 g/cm^3, and calcium (Ca) has a density of about 1.55 g/cm^3 at STP.
#SPJ2
B. freezing-point depression
C. molar freezing-point constant
D. molal melting-point constant
E. molal boiling-point constant
CuSO4 + 2NaOH mc009-2.jpg Cu(OH)2 + Na2SO4
2NaOH + H2CO3 mc009-3.jpg Na2CO3 + 2NaOH
Pb(NO3)2 + Na2SO4 mc009-4.jpg 2NaNO3 + PbSO4
Answer:
The correct option is: Fe₂O₃ + 3CO → 2Fe + 3CO₂
Explanation:
An oxidation-reduction reaction, also known as the redox reaction, is a chemical reaction in which there is simultaneous transfer of electrons from one species to another.
The species that gains electrons gets reduced. Whereas, species that loses electrons gets oxidized.
Among the given options, only reaction 1 is a redox reaction:
Fe₂O₃ + 3CO → 2Fe + 3CO₂
Reason- In this reaction, iron (Fe) gains electrons and gets reduced from +3 oxidation state in Fe₂O₃ to 0 oxidation state in Fe. Whereas, carbon (C) loses electrons and gets oxidized from +2 oxidation state in CO to +4 oxidation state in CO₂.
Since both the oxidation and reduction reactions are occurring simultaneously.
Therefore, it is an redox reaction.
B. 1s2
C. 1s22s1
D. 1s22s2
The electronic configuration is the system of the electron distribution in the shells of the atom. The electronic configuration for He is 1s² as it is a noble gas. Thus, option B is correct.
The electronic configuration is the depiction of the electrons in the orbital level of the atoms around the nucleus. The electrons are distributed in the four orbitals namely, s, p, d, and f.
The orbitals have different sub-levels and can accommodate a different number of electrons. The electronic configuration of helium atom with atomic number 2 can be written as, 1s².
The s orbital can accommodate only two electrons in them and helium having only two electrons gets completely filled. Helium being the inert gas has the most stable configuration.
Therefore, 1s² is the electronic configuration of He.
Learn more about electronic configuration here:
#SPJ5
Answer:
B. 1s2
this is your answer....
-facts
-personal viewpoints
-none of the above
Answer:
Facts
Explanation:
You can literally read the lesson it tells you science is
all about facts