Answer:
CH2 --> sp2 hybridization.
C-C-C --> sp hybridization.
Explanation:
The CH2 has two simple bonds to the H and one double bond to another C. This means that in the hybridization of this C are involved 3 orbitals: 1 s and 2 p, resulting in a sp2 hybridization.
The C-C-C central carbon has two double bonds, one to each C. This means that in the hybridization of this C are involved 2 orbitals: 1 s and 1 p, resulting in a sp hybridization.
The hybridization of the CH2 carbon is 'sp2' and the middle CCC carbon's hybridization in all mentioned molecules is 'sp'.
The carbon in CH2 in all the three molecules, H2CCH2, H2CCCH2, and H2CCCCH2 is always connected to two other atoms: a carbon and a hydrogen. Therefore, its hybridization is
sp2
. The middle carbon in ccc sequence is also linked to two other carbons only. Its hybridization is also
sp
. To summarize, the CH2 carbon's hybridization in all the molecules is
sp2
and the middle CCC carbon's hybridization in all the molecules is
sp
.
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B. It stops the products from being formed from the intermediate state.
C. It slows down the overall chemical reaction so it does not happen too quickly.
D. It provides reactants with sufficient energy for bonds to break and reform.
Answer: The description it provides reactants with sufficient energy for bonds to break and reform best explains the role of activation energy in a chemical reaction.
Explanation:
Activation energy is defined as the minimum amount of required energy so that a chemical reaction can initiate.
As a result, it provides the reactants with certain amount of energy so that they will get the necessary amount of energy to break their bond and then form new bonds.
Thus, we can conclude that the description it provides reactants with sufficient energy for bonds to break and reform best explains the role of activation energy in a chemical reaction.
H2 + O2 -> H2O
If 20 g of hydrogen is reacted with 32 g of oxygen to produce 9 g of water, the percentage yield is 5%.
Percent yield is the ratio of the actual yield times the theoretical yield to 100. When the actual and theoretical yield are equal, the percentage yield is 100%. So if the actual yield is less than the theoretical yield then the percentage yield is less than 100%. This situation may arise due to the incompleteness of the reaction or the loss of the sample during the recovery process.
According to the stoichiometry of reaction of formation of water,
4 g hydrogen gives 36 g water, thus, 20 g hydrogen gives 20×36/4=180 g water which is theoretical yield.
So, the percent yield=observed yield/theoretical yield×100
percent yield=9/180×100=5%.
Thus, if 20 g of hydrogen is reacted with 32 g of oxygen to produce 9 g of water, the percentage yield is 5%.
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Answer:
12.5%
Explanation:
32/16 = 2 moles of oxygen
2 x 18.01 x 2/1 = 72.04 g of H2O
9/72.04 x 100 = 12.5%
balanced equation: 2H2 + O2 → 2H2O
limiting reactant is oxygen