A 35.65 g sample of NaOH contains 0.8910 moles of NaOH.
The mole, denoted by the sign "mol," is the volume of a system that has the same number of atoms in 0.012 kilograms of carbon-12 as there are elementary particles.
The mole, often known as mol, is a SI unit used to measure how many particles are present in a given substance. A mole is made up of 6.02214179 atoms or other fundamental building blocks like molecules.
Mass off NaOH = 39.997
given = 35.65 g of NaOH
No of moles of NaOH =35.65 g of NaOH × 1 mol NaOH /40.01 g
No of moles of NaOH = 0.8910 moles.
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Answer:
0.8910 mols of NaOH in a 35.65 g sample of NaOH
Explanation:
Mass off NaOH = 39.997
given = 35.65 g of NaOH
35.65 g of NaOH * 1 mol NaOH = 0.8910, since there are 4 sig figs.
/40.01 g
7 billion years ago
11 billion years ago
13 billion years ago
The correct answer is 13 billion years ago.
The Big Bang theory is the existing cosmological model for the apparent universe from the most primitive known periods via its consequent large scale evolution. The model illustrates that how the expansion of the universe took place from a very high temperature and high-density state and provides a complete illustration for a wide array of processes comprising the existence of cosmic microwave background, light elements, Hubble's law, and large scale structure.
The complete measurements of the rate of expansion of the universe put the Big Bang at approximately 13.8 billion years ago, that is, thus regarded as the age of the universe.
Q < Keq
Q > Keq
Q = Keq
Answer:
A. Q = Keq
B. Equilibrium quantities of reactants and products
C. Q > Keq
D. System will shift toward reactants
E. Overabundance of reactants
F. System will shift toward products
Here are all the answers :)
To fill in the table about equilibrium, if Q < Keq the reaction will move right (produce more products), if Q > Keq it will move left (produce more reactants), and if Q = Keq the system is at equilibrium with no net change.
To complete the first row in the table about a system at equilibrium, we need to fill in the missing information based on the reaction quotient (Q) and the equilibrium constant (Keq).
For a system at equilibrium, not only is Q = Keq, but also the change in Gibb's free energy (ΔG) is zero. This relationship can be represented as 0 ΔG° + RT ln K at equilibrium.