MATHEMATICS HIGH SCHOOL

What is the volume of a cube with an edge length of 0.8 m?Enter your answer in the box.

m³=

Answers

Answer 1

Answer: 0.8 * 0.8 * 0.8 is the volume. 0.512 m3.

Answer 2

Answer:

Answer:

Just took the quiz ;-; the answer is "0.512"

Thank me later xD

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A mouse population starts with 2,000 mice and grows at a rate of 5% per year. The number of mice after t years can be modeled by the equation, P(t)=2000(1.05)^t. What is the average rate of change in the number of mice between the second year and the fifth year, rounded to the nearest whole number?

Answers

m=2000 (1.05)^2 for 2 years
so m=2205

m=2000 (1.05)^5 for 5 years
so m= approximately 2553

2553-2000
=553

That's your average rate of change in mice between two years and five years.

(y-4)6

help please....

Answers

6y-24

6(y) =6y
4(6)= 24

35.4% expressed as a decimal becomes
A. 0.354.
B. 3.54.
C. 354.
D. 35.0

Answers

To convert a percentage into a decimal, you divide it by 100. So in this case, we do 35.4/100 = 0.354. Therefore A is the correct answer.

Point I is on line segment H
J
‾
HJ
. Given
I
J
=
3
x
+
3
,
IJ=3x+3,
H
I
=
3
x
−
1
,
HI=3x−1, and
H
J
=
3
x
+
8
,
HJ=3x+8, determine the numerical length of
H
J
‾
.
HJ
.

Answers

Answer:

Step-by-step explanation:

the answer is 14

Which statements are true for the functions g(x) = x2 and h(x) = –x2 ? Check all that apply.For any value of x, g(x) will always be greater than h(x).
For any value of x, h(x) will always be greater than g(x).
g(x) > h(x) for x = -1.
g(x) < h(x) for x = 3.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).

Answers

if x=0 then they have same value

1st and 2nd options are out

for x=-1
g(-1)=1
h(-1)=-1
3rd is true

4th
false

for all values except zero, g(x)>h(x)

correct ones are

g(x) > h(x) for x = -1.
For positive values of x, g(x) > h(x).
For negative values of x, g(x) > h(x).

Answer: g(x) > h(x) for x = -1.

For positive values of x, g(x) > h(x).

For negative values of x, g(x) > h(x).

Step-by-step explanation:

Given functions: $g(x)=x^2$ and $h(x)=-x^2$

When x=0, $g(0)=0^2=0$ and $h(0)=-0^2=0$

∴ at x=0, g(x)=h(0)

Therefore the statements "For any value of x, g(x) will always be greater than h(x)." and "For any value of x, h(x) will always be greater than g(x)." are not true.

When x=-1, $g(-1)=(-1)^2=1$ and $h(-1)=-(-1)^2=-1$